I need to add an average field to a file. I can create it in an on-screen report and it does what I need using the awk command but I can't get it to create a new file with the additional field. Here's what I'm working with:
Hi,
I have a comma delimited text file where character fields (as opposed to numeric and date fields) are always enclosed with double quotes. Records are separated by the newline character. In a shell script I would like to split a particular field into two separate fields (enclosed with double... (4 Replies)
Hi Everybody,
I have an layout file like below
f1 1 char 10,
f2 11 char 2,
f3 13 char 1,
lineend 14 char 1
Their I need to add a new field which would be like
f5 char 3,
f6 char 2
The o/p should be
f1 1 char 10,
f2 11 char 2,
f3 13 char 1,
f5 14 char 3,
f6 17 char 2 (3 Replies)
Hi,
I have a file that has data in it that says
00:01:48.233 1212
00:01:56.233 345
00:09:01.221 5678
00:12:23.321 93444
The file has more line than this but i just wanted to put in a snippet to ask how I would get the highest number with time stamp into another file. So from the above... (2 Replies)
Hi,
I have two text files. Need to create a third text file extracting specific data from first two existing files..
Text File 1: Format contains:
SQL*Loader: Release 10.2.0.1.0 - Production on Wed Aug 4 21:06:34 2010
some text ............so on...and somwhere text like:
Record 1:... (1 Reply)
Hello,
I'm trying to get a value based on a comparison of two fields, this is:
file1
687.45
687.18
687.322
687.405
686.865
file 2
685 6.43
686 6.43
687 6.42
688 6.42 (3 Replies)
Hi experts,
I need to print the first field first then last two fields should come next and then i need to print rest of the fields.
Input :
a1,abc,jsd,fhf,fkk,b1,b2
a2,acb,dfg,ghj,b3,c4
a3,djf,wdjg,fkg,dff,ggk,d4,d5
Expected output:
a1,b1,b2,abc,jsd,fhf,fkk... (6 Replies)
Hi All,
We are trying to pull out data from below table, the table contains four fields and out of which last two fields are having sub-fields with delimiter $, we want to identify number "1" position in the 3rd field and from 4th field need to extract the information from the same position.
... (4 Replies)
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Here are the reasons for this change:
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Discussion started by: Neo
6 Replies
LEARN ABOUT DEBIAN
plan9-join
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If one of the file names is the
standard input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Input fields are normally separated spaces or tabs; output fields by space. In this case, multiple separators count as one, and leading
separators are discarded.
The following options are recognized, with POSIX syntax.
-a n In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-v n Like -a, omitting output for paired lines.
-e s Replace empty output fields by string s.
-1 m
-2 m Join on the mth field of file1 or file2.
-jn m Archaic equivalent for -n m.
-ofields
Each output line comprises the designated fields. The comma-separated field designators are either 0, meaning the join field, or
have the form n.m, where n is a file number and m is a field number. Archaic usage allows separate arguments for field designators.
-tc Use character c as the only separator (tab character) on input and output. Every appearance of c in a line is significant.
EXAMPLES
sort /etc/passwd | join -t: -1 1 -a 1 -e "" - bdays
Add birthdays to the /etc/passwd file, leaving unknown birthdays empty. The layout of /adm/users is given in passwd(5); bdays con-
tains sorted lines like
tr : ' ' </etc/passwd | sort -k 3 3 >temp
join -1 3 -2 3 -o 1.1,2.1 temp temp | awk '$1 < $2'
Print all pairs of users with identical userids.
SOURCE
/src/cmd/join.c
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b -ky,y; with -t, the sequence is that of sort -tx -ky,y.
One of the files must be randomly accessible.
JOIN(1)