04-13-2007
How to print a % within a printf() function using awk
Here is the code I'm using
{
printf("%11d %4.2f\% %4.2f\%\n", $1,$2,$3);
}
I want the output to look something like
1235415234 12.24% 52.46%
Instead it looks something like
319203842 42.27\%4.2f\%
How do I just print a "%" without awk or printf thinking I'm trying to do something. Blackslash escapes don't seem to work.
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LEARN ABOUT DEBIAN
explain_printf_or_die
explain_printf_or_die(3) Library Functions Manual explain_printf_or_die(3)
NAME
explain_printf_or_die - formatted output conversion and report errors
SYNOPSIS
#include <libexplain/printf.h>
int explain_printf_or_die(const char *format);
int explain_printf_on_error(const char *format);
DESCRIPTION
The explain_printf_or_die function is used to call the printf(3) system call. On failure an explanation will be printed to stderr, obtained
from the explain_printf(3) function, and then the process terminates by calling exit(EXIT_FAILURE).
The explain_printf_on_error function is used to call the printf(3) system call. On failure an explanation will be printed to stderr,
obtained from the explain_printf(3) function, but still returns to the caller.
format The format, exactly as to be passed to the printf(3) system call.
RETURN VALUE
The explain_printf_or_die function only returns on success, see printf(3) for more information. On failure, prints an explanation and
exits, it does not return.
The explain_printf_on_error function always returns the value return by the wrapped printf(3) system call.
EXAMPLE
The explain_printf_or_die function is intended to be used in a fashion similar to the following example:
int result = explain_printf_or_die(format);
SEE ALSO
printf(3)
formatted output conversion
explain_printf(3)
explain printf(3) errors
exit(2) terminate the calling process
COPYRIGHT
libexplain version 0.52
Copyright (C) 2010 Peter Miller
explain_printf_or_die(3)