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Substitution not working in ksh
Post 302113943 by arsheshadri on Wednesday 11th of April 2007 10:03:56 AM
04-11-2007
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Hello,
I thought it was possible to use several time a #! entry on a script but it doesn't seems to work. My need is to have a part of a ksh script without substitution so it would look like
#!/bin/ksh
--
first part
---
#!/bin/ksh -f
--
part without substitution
--
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hi,
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Hello,
In bash I can use the following:
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LEARN ABOUT DEBIAN
zip_name_locate
ZIP_NAME_LOCATE(3) Library Functions Manual ZIP_NAME_LOCATE(3) NAME
zip_name_locate - get index of file by name LIBRARY
libzip (-lzip) SYNOPSIS
#include <zip.h> int zip_name_locate(struct zip *archive, const char *fname, int flags); DESCRIPTION
The zip_name_locate function returns the index of the file named fname in archive. If archive does not contain a file with that name, -1 is returned. The are specified by or'ing the following values, or 0 for none of them. ZIP_FL_NOCASE Ignore case distinctions. ZIP_FL_NODIR Ignore directory part of file name in archive. RETURN VALUES
zip_name_locate returns the index of the file named fname or -1, if archive does not contain an entry of that name. ERRORS
The zip_name_locate function fails and sets the error information to ZIP_ER_NOENT if no entry of the name fname is found in the archive. If one of the arguments is invalid, the error information is set to ZIP_ER_INVAL. SEE ALSO
libzip(3), zip_get_name(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH October 4, 2006 ZIP_NAME_LOCATE(3)