Sponsored Content
Full Discussion: pad Zeros
Top Forums UNIX for Dummies Questions & Answers pad Zeros Post 302113798 by ghostdog74 on Tuesday 10th of April 2007 09:39:21 AM
Old 04-10-2007
Code:
printf "%08d" 16

 

7 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

number pad?

Is there anyway to use the fr*$%& number pad in VI? Anyway? Anyway at all? All it does now random movements and inserts of characters (2 Replies)
Discussion started by: nelsonenzo
2 Replies

2. Shell Programming and Scripting

Pad zeros to a number

Pad zeros to a number and assign it to a variable like i get 1 in $i ,i want it to be $i as 01 (6 Replies)
Discussion started by: anumkoshy
6 Replies

3. UNIX for Dummies Questions & Answers

pad

Hi All I need a pad a . to befoure a last digi ex 1258 --> 125.8 help to do thanks (4 Replies)
Discussion started by: nalakaatslt
4 Replies

4. Programming

How to right pad with zeros using sprintf?

I need to right-pad with zeros a string by using (s)printf. I looked up the manual and tried with printf("%-19s", buffer); which right-pad the string with spaces. So I tried printf("%019s", buffer); which left-pad the string with zeros. So I tried both printf("%-019s", buffer);... (9 Replies)
Discussion started by: emitrax
9 Replies

5. Shell Programming and Scripting

Pad Zeros at the end

I have number/strings like below input =23412133 output = 234121330000 (depends on the number give at runtime) i need to padd zeros based on runtime input . i tried below printf ' %d%04d\n', "23412133"; But the precision 4 is static here how can i pass this as runtime input. i am... (11 Replies)
Discussion started by: greenworld123
11 Replies

6. Shell Programming and Scripting

How to pad with leading zeros for current time?

I'm using cygwin bash to submit scheduled tasks (kinda like cron jobs) in windows and the following script is giving me grief. I need to format the current time with leading zeros before 10AM for the hour field. In this example, I manually typed in "09:50" instead of using the `printf...`... (2 Replies)
Discussion started by: siegfried
2 Replies

7. UNIX for Beginners Questions & Answers

Pad 0 to the right

I need to pad 0 to a number on the right. to make it 9 digit in total. My number is 2457 output should be 245700000 Please do wrap your samples/codes into CODE TAGS as per forum rules. (3 Replies)
Discussion started by: varun22486
3 Replies
CUBRID_NEXT_RESULT(3)							 1						     CUBRID_NEXT_RESULT(3)

cubrid_next_result - Get result of next query when executing multiple SQL statements

SYNOPSIS
bool cubrid_next_result (resource $result) DESCRIPTION
The cubrid_next_result(3) function is used to get results of next query if multiple SQL statements are executed and CUBRID_EXEC_QUERY_ALL flag is set upon cubrid_execute(3). PARAMETERS
o $result -$result comes from a call to cubrid_execute(3) RETURN VALUES
TRUE, when process is successful. FALSE, when process is unsuccessful. EXAMPLES
Example #1 cubrid_next_result(3) example <?php $conn = cubrid_connect("127.0.0.1", 33000, "demodb", "dba"); $sql_stmt = "SELECT * FROM code; SELECT * FROM history WHERE host_year=2004 AND event_code=20281"; $res = cubrid_execute($conn, $sql_stmt, CUBRID_EXEC_QUERY_ALL); get_result_info($res); cubrid_next_result($res); get_result_info($res); function get_result_info($req) { printf(" ------------ get_result_info -------------------- "); $row_num = cubrid_num_rows($req); $col_num = cubrid_num_cols($req); $column_name_list = cubrid_column_names($req); $column_type_list = cubrid_column_types($req); $column_last_name = cubrid_field_name($req, $col_num - 1); $column_last_table = cubrid_field_table($req, $col_num - 1); $column_last_type = cubrid_field_type($req, $col_num - 1); $column_last_len = cubrid_field_len($req, $col_num - 1); $column_1_flags = cubrid_field_flags($req, 1); printf("%-30s %d ", "Row count:", $row_num); printf("%-30s %d ", "Column count:", $col_num); printf(" "); printf("%-30s %-30s %-15s ", "Column Names", "Column Types", "Column Len"); printf("------------------------------------------------------------------------------ "); $size = count($column_name_list); for($i = 0; $i < $size; $i++) { $column_len = cubrid_field_len($req, $i); printf("%-30s %-30s %-15s ", $column_name_list[$i], $column_type_list[$i], $column_len); } printf(" "); printf("%-30s %s ", "Last Column Name:", $column_last_name); printf("%-30s %s ", "Last Column Table:", $column_last_table); printf("%-30s %s ", "Last Column Type:", $column_last_type); printf("%-30s %d ", "Last Column Len:", $column_last_len); printf("%-30s %s ", "Second Column Flags:", $column_1_flags); printf(" "); } ?> The above example will output: ------------ get_result_info -------------------- Row count: 6 Column count: 2 Column Names Column Types Column Len ------------------------------------------------------------------------------ s_name char 1 f_name varchar 6 Last Column Name: f_name Last Column Table: code Last Column Type: varchar Last Column Len: 6 Second Column Flags: ------------ get_result_info -------------------- Row count: 4 Column count: 5 Column Names Column Types Column Len ------------------------------------------------------------------------------ event_code integer 11 athlete varchar 40 host_year integer 11 score varchar 10 unit varchar 5 Last Column Name: unit Last Column Table: history Last Column Type: varchar Last Column Len: 5 Second Column Flags: not_null primary_key unique_key SEE ALSO
cubrid_execute(3). PHP Documentation Group CUBRID_NEXT_RESULT(3)
All times are GMT -4. The time now is 06:06 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy