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Top Forums Shell Programming and Scripting Outputting from two input files. Post 302113754 by anbu23 on Tuesday 10th of April 2007 02:31:24 AM
Old 04-10-2007
Quote:
Originally Posted by Liguidsoul
So it's possible, but less efficient? How would we do that anyway, say, with a loop like this:

for ******
do
******
done > loop.out
Code:
while read nm day
do
  grep $nm file1 | read name no
  echo $name $day $no
done <file2

or

Code:
awk ' { arr[$1] = arr[$1] ? arr[$1]" "$2 : $2 }
END {
     for( key in arr ) { print key " " arr[key] }
}' file2 file1

 

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GREGORIANTOJD(3)							 1							  GREGORIANTOJD(3)

gregoriantojd - Converts a Gregorian date to Julian Day Count

SYNOPSIS
int gregoriantojd (int $month, int $day, int $year) DESCRIPTION
Valid Range for Gregorian Calendar 4714 B.C. to 9999 A.D. Although this function can handle dates all the way back to 4714 B.C., such use may not be meaningful. The Gregorian calendar was not instituted until October 15, 1582 (or October 5, 1582 in the Julian calendar). Some countries did not accept it until much later. For exam- ple, Britain converted in 1752, The USSR in 1918 and Greece in 1923. Most European countries used the Julian calendar prior to the Grego- rian. PARAMETERS
o $month - The month as a number from 1 (for January) to 12 (for December) o $day - The day as a number from 1 to 31 o $year - The year as a number between -4714 and 9999 RETURN VALUES
The julian day for the given gregorian date as an integer. EXAMPLES
Example #1 Calendar functions <?php $jd = GregorianToJD(10, 11, 1970); echo "$jd "; $gregorian = JDToGregorian($jd); echo "$gregorian "; ?> SEE ALSO
jdtogregorian(3), cal_to_jd(3). PHP Documentation Group GREGORIANTOJD(3)
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