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Top Forums Shell Programming and Scripting Help needed in character replacement in Korn Shell Post 302112568 by stevefox on Thursday 29th of March 2007 02:24:43 AM
Old 03-29-2007
Question Help needed in character replacement in Korn Shell

How do I replace a space " " character at a particular position in a line?

e.g. I have a file below

Code:
$ cat i2
111 002 A a
33 0011 B c
2222 003 C a


I want all the 1st spaces to be replaced with forward slash "/" and the 3rd spaces to have 5 spaces to get the output below:


Code:
111/002 AAA     a
33/0011 BBB     c
2222/003 CCC     b

I created a shell which would achieve this but I'm looking for a easier way.

Code:
$ cat test.ksh
#!/bin/ksh

cut -d' ' -f1 < $1 > 1st_word
cut -d' ' -f3 < $1 > 3rd_word

while read line
do

sed -e "s/$line /$line\//g" $1 | grep $line

done < 1st_word > tmp_ouput


while read line
do

sed -e "s/$line /$line     /g" tmp_ouput1 | grep $line

done < 3rd_word


Any help will be appreciated

Steve
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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