Hi,
This was very unusual situation I never came across & we have SUN engineers working on this.
We have Sun Fire V240 Server, 2 1.5-GHz UltraSPARC IIIi CPU, Solaris 9 Installed
During the boot-up it gives following message,
<date> <server name> unix : KEY in LOCKED position ignoring... (5 Replies)
Dear experts,
Im having an unusual problem and its been giving me a bad headache.
I have the script below #!/usr/bin/sh -x
ticketinputdir=/IN_DATA1/tickets
ticketoutputdir=/IN_DATA2
YDAY=`env TZ=A12B date '+%Y%m%d'`
for i in INA INB INC IND INE
do
mkdir $ticketoutputdir/$i/$YDAY... (4 Replies)
Hi, i;m beginner of Unix, i trying to use crontab to zip my log file automatically, below is my coding, some of the statement i don't know whether is correct or not. Pls help:)
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 9 |... (4 Replies)
I try to find the first day of our calender. So I used this script ...
echo -n "The week of the date 01jan0001 : "
echo -n `date -d 00010101 +%A`
echo
But its shows error
bash-3.1$ sh first_day.shThe week of the date 01jan0001 : date: invalid date `00010101' (3 Replies)
Hi
I am trying to schedule a job through Autosys through UNIX on a particular day of every month (for example 20th of every month). Can some one please help me whats the command or whats the process to run on that particular day of month.
Thank you, (2 Replies)
Hello,
I am working in office, where, more than 60 clients machines (only 16 machines are on windows) are there and one server Centos Server, I have configured clients with server, so that internet will be used form only one IP. Only 1 ip is assigned, but now a days, my client machines are... (2 Replies)
Hello Awk'inas/Sed'ers;
This is keep ringing on my mind for a while, onto play in calender with awk or sed :cool:. Given a date, month and Year would like to find out the day corresponding to it. Am still a noob on awk and sed, hence would like to learn it from your responses.
Here it is;... (11 Replies)
Friends need assistance in getting a script either on shell or perl. Below is the situation
Taking Today's calender into consideration with Month,Day,Year current .Using that i would like give number of days to get its month,day,year for future or past calender depending on the + or - days... (8 Replies)
I have CGI Perl script that contains date column and date popup will be displayed from inline calender.
I had a html script for the same and converted the same to CGI script.
html page worked fine but no luck with CGI script.
Could anyone please look into the below script and let me know... (1 Reply)
Discussion started by: scriptscript
1 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)