I have file1 and file2:
file1:
11 xxx kksd ...
22 kkk kdsglg...
33 sss kdfjdksa...
44 kdsf dskjfkas ...
hh kdkf kdkkd..
jg dkf dfkdk ...
...
file2:
jg
22
hh
...
I need to check each line of file1. if the field one is in file2, I will keep it; if not, the whole line will be... (17 Replies)
I have searched about 30 threads, a load of Google pages and cannot find what I am looking for. I have some of the parts but not the whole. I cannot seem to get the puzzle fit together.
I have three folders, two of which contain different versions of multiple files, dist/file1.php dist/file2.php... (4 Replies)
Hi, all:
I've got two folders, say, "folder1" and "folder2".
Under each, there are thousands of files.
It's quite obvious that there are some files missing in each. I just would like to find them. I believe this can be done by "diff" command.
However, if I change the above question a... (1 Reply)
I have four files, I need to compare these files together.
As such i know "sdiff and comm" commands but these commands compare 2 files together. If I use sdiff command then i have to compare each file with other which will increase the codes.
Please suggest if you know some commands whcih can... (6 Replies)
Please help me with awk.I have two files with the below details
file1
123456789 2012
987654321 2011
a1234567892012
a1234abcde2012
b1234567892012
c1234567892012
98765a12342012
file2
a1234
01234
b1234
33333
I need to check whether the items in file2 is present in file1 .If it is... (2 Replies)
I want to compare two files, and search for items that are in both. Then override the first file with that containing only elements which were in both files. I imagine something with diff, but not sure.
File 1
One
Two
Three
Four
Five
File 2
One
Three
Four
Six
Eight (2 Replies)
I have this code
awk 'NR==FNR{a=$1;next} a' file1 file2
which does what I need it to do, but for only two files. I want to make it so that I can have multiple files (for example 30) and the code will return only the items that are in every single one of those files and ignore the ones... (7 Replies)
hi all,
Thanks to all for your great help...
I have a scenario that I have two files (file1 & file2). I need to compare two files entire row by row and share the output if any discrepancies within two files.
File1:
DB1|TB1|C1,C3
DB2|TB2|C1,C2
DB3|TB3|C1,C2,C3,C4
File2:
... (2 Replies)
Discussion started by: Selva_2507
2 Replies
LEARN ABOUT DEBIAN
dpkg::changelog::parse
Dpkg::Changelog::Parse(3) libdpkg-perl Dpkg::Changelog::Parse(3)NAME
Dpkg::Changelog::Parse - generic changelog parser for dpkg-parsechangelog
DESCRIPTION
This module provides a single function changelog_parse() which reproduces all the features of dpkg-parsechangelog.
Functions
my $fields = changelog_parse(%opt)
This function will parse a changelog. In list context, it return as many Dpkg::Control object as the parser did output. In scalar context,
it will return only the first one. If the parser didn't return any data, it will return an empty in list context or undef on scalar
context. If the parser failed, it will die.
The parsing itself is done by an external program (searched in the following list of directories: $opt{libdir},
/usr/local/lib/dpkg/parsechangelog, /usr/lib/dpkg/parsechangelog) That program is named according to the format that it's able to parse. By
default it's either "debian" or the format name lookep up in the 40 last lines of the changelog itself (extracted with this perl regular
expression "schangelog-format:s+([0-9a-z]+)W"). But it can be overridden with $opt{changelogformat}. The program expects the content of
the changelog file on its standard input.
The changelog file that is parsed is debian/changelog by default but it can be overridden with $opt{file}.
All the other keys in %opt are forwarded as parameter to the external parser. If the key starts with "-", it's passed as is. If not, it's
passed as "--<key>". If the value of the corresponding hash entry is defined, then it's passed as the parameter that follows.
1.16.15 2014-06-05 Dpkg::Changelog::Parse(3)