Sponsored Content
Full Discussion: grep to handle a 0 result
Top Forums UNIX for Dummies Questions & Answers grep to handle a 0 result Post 302105873 by tayyabq8 on Monday 5th of February 2007 09:50:59 AM
Old 02-05-2007
grep -c "string" also gives you the count of lines then why are you still piping the output to wc -l, it'll always give you the output as "1", please remove it and try.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

To have a numeric result from grep

I am new to unix. i need to know how to use grep to grep and expression from a file. and pass the result as a 0 for found and 1 for not found. I can only go up to grep 'Checking Subscription Status' ranos.log. Please help. Thank you. (2 Replies)
Discussion started by: Hak Dee
2 Replies

2. Shell Programming and Scripting

How ro handle backslash character in grep?

Hi , I am doing invert grep using -v but the string contain "/" which break the grep command and it do not skip the lines with "/" on it. Diffu.txt ======== 1159c1159 < <td align="right" valign="middle" class="paddingRight2px" id="featureListItemChannelButton7466"> --- > <td... (1 Reply)
Discussion started by: rajbal
1 Replies

3. UNIX for Advanced & Expert Users

How to handle backslash in grep string

Hi , I am doing invert grep using -v but the string contain "/" which break the grep command and it do not skip the lines with "/" on it. Diffu.txt ======== 1159c1159 < <td align="right" valign="middle" class="paddingRight2px" id="featureListItemChannelButton7466"> --- > <td... (6 Replies)
Discussion started by: rajbal
6 Replies

4. Shell Programming and Scripting

How to negate grep result?

Here is my script so far: set dirs = ` find . -name "message.jar" 2> /dev/null | cut -d "/" -f 2 ` | uniq foreach dir ( $dirs ) if (grep $dir/* someText==null) --> how do I write this in script? print $dir end end (4 Replies)
Discussion started by: mmdawg
4 Replies

5. UNIX for Dummies Questions & Answers

Grep alternative to handle large numbers of files

I am looking for a file with 'MCR0000000716214' in it. I tried the following command: grep MCR0000000716214 * The problem is that the folder I am searching in has over 87000 files and I am getting the following: bash: /bin/grep: Arg list too long Is there any command I can use that can... (6 Replies)
Discussion started by: runnerpaul
6 Replies

6. Shell Programming and Scripting

pipe result from grep

Trying to create a command line script to look for all files matching a pattern, grep for a specific value in each file, and write out the filename long list. It's possible the filename won't containe the value. { echo “Running....” for fname in 811_Intermediate_File_* do grep -l... (3 Replies)
Discussion started by: gavineq
3 Replies

7. UNIX for Dummies Questions & Answers

grep, expecting 1 result, getting more

Hi Please take a look below, I'm grepping for /app/oracle and would like explicitly that result and not /app/oracle/admin as well. # cat /tmp/fs.list /app/oracle /app/oracle/admin # cat /tmp/fs.list | grep -w "/app/oracle" /app/oracle /app/oracle/admin (3 Replies)
Discussion started by: s1ckle
3 Replies

8. Shell Programming and Scripting

How to handle Numerical result out of range?

i have this code: a=hello999999999999999999999999999999999999999999999999999999999 b=`echo ${a} | tr -d ''` if ; then echo "Zero" fi but when I execute this I am having this error: Numerical result out of range Anyone know how to handle this? Thanks!! (4 Replies)
Discussion started by: h0ujun
4 Replies

9. UNIX for Dummies Questions & Answers

Bash - CLI - grep - Passing result to grep through pipe

Hello. I want to get all modules which are loaded and which name are exactly 2 characters long and not more than 2 characters and begin with "nv" lsmod | (e)grep '^nv???????????? I want to get all modules which are loaded and which name begin with "nv" and are 2 to 7 characters long ... (1 Reply)
Discussion started by: jcdole
1 Replies

10. Shell Programming and Scripting

Grep result from dd command

Hi, I am running following command in a bash script for testing IO and use grep to get throughput number, but it did not work, it displayed everything: dd if=/dev/zero of=/dev/null bs=1G count=1 oflag=dsync | grep bytes | awk '{print $7}' 1+0 records in 1+0 records out 536870912 bytes... (2 Replies)
Discussion started by: hce
2 Replies
ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
All times are GMT -4. The time now is 05:15 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy