I am new to unix. i need to know how to use grep to grep and expression from a file. and pass the result as a 0 for found and 1 for not found. I can only go up to grep 'Checking Subscription Status' ranos.log. Please help. Thank you. (2 Replies)
Hi ,
I am doing invert grep using -v but the string contain "/" which break the grep command and it do not skip the lines with "/" on it.
Diffu.txt
========
1159c1159
< <td align="right" valign="middle" class="paddingRight2px" id="featureListItemChannelButton7466">
---
> <td... (1 Reply)
Hi ,
I am doing invert grep using -v but the string contain "/" which break the grep command and it do not skip the lines with "/" on it.
Diffu.txt
========
1159c1159
< <td align="right" valign="middle" class="paddingRight2px" id="featureListItemChannelButton7466">
---
> <td... (6 Replies)
Here is my script so far:
set dirs = ` find . -name "message.jar" 2> /dev/null | cut -d "/" -f 2 ` | uniq
foreach dir ( $dirs )
if (grep $dir/* someText==null) --> how do I write this in script?
print $dir
end
end (4 Replies)
I am looking for a file with 'MCR0000000716214' in it. I tried the following command:
grep MCR0000000716214 *
The problem is that the folder I am searching in has over 87000 files and I am getting the following:
bash: /bin/grep: Arg list too long
Is there any command I can use that can... (6 Replies)
Trying to create a command line script to look for all files matching a pattern, grep for a specific value in each file, and write out the filename long list. It's possible the filename won't containe the value.
{
echo “Running....”
for fname in 811_Intermediate_File_*
do
grep -l... (3 Replies)
Hi
Please take a look below, I'm grepping for /app/oracle and would like explicitly that result and not /app/oracle/admin as well.
# cat /tmp/fs.list
/app/oracle
/app/oracle/admin
# cat /tmp/fs.list | grep -w "/app/oracle"
/app/oracle
/app/oracle/admin (3 Replies)
i have this code:
a=hello999999999999999999999999999999999999999999999999999999999
b=`echo ${a} | tr -d ''`
if ; then
echo "Zero"
fi
but when I execute this I am having this error: Numerical result out of range
Anyone know how to handle this?
Thanks!! (4 Replies)
Hello.
I want to get all modules which are loaded and which name are exactly 2 characters long and not more than 2 characters and begin with "nv"
lsmod | (e)grep '^nv????????????
I want to get all modules which are loaded and which name begin with "nv" and are 2 to 7 characters long
... (1 Reply)
Hi,
I am running following command in a bash script for testing IO and use grep to get throughput number, but it did not work, it displayed everything:
dd if=/dev/zero of=/dev/null bs=1G count=1 oflag=dsync | grep bytes | awk '{print $7}'
1+0 records in
1+0 records out
536870912 bytes... (2 Replies)
Discussion started by: hce
2 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)