Sponsored Content
Top Forums UNIX for Dummies Questions & Answers How Can I Easily Determine If A File Has been Added to a Directory Post 302105260 by sb008 on Wednesday 31st of January 2007 05:56:39 PM
Old 01-31-2007
Quote:
Originally Posted by goodmis
I am uploading files that need to be processed prior to uploading. I will put the files in a directory. My question is how can I write an easy process to kick off a script once a file has been added? Is there an easy way to determine if a file has been added to a directory?

Thanks
Why you ask the same question in 2 forums?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

determine owner directory permissions from within the directory

From within a directory, how do I determine whether I have write permission for it. test -w pwd ; echo ? This doesn't work as it returns false, even though I have write permission. (4 Replies)
Discussion started by: Sniper Pixie
4 Replies

2. UNIX for Advanced & Expert Users

cannot determine current directory

Hi, when I execute some simple commands on my solaris system, I am getting the following warning message: Could anybody tell me what could be the reason Ex:- If I give the command, which ls Warning: cannot determine current directory ... (15 Replies)
Discussion started by: axes
15 Replies

3. UNIX for Advanced & Expert Users

How Can I Easily Determine If A File Has been Added to a Directory

I am uploading files that need to be processed prior to uploading. I will put the files in a directory. My question is how can I write an easy process to kick off a script once a file has been added? Is there an easy way to determine if a file has been added to a directory? Thanks (7 Replies)
Discussion started by: goodmis
7 Replies

4. Shell Programming and Scripting

[Perl] Determine directory name

Hi there, I wonder if it is possible the determine a name of a directory which is different on various hosts. Let me try to explain. I have the directory /tmp/dir1/dir2/canchangedir. This directory name is different on various hosts. I need to use the directory name, independent from the... (2 Replies)
Discussion started by: ejdv
2 Replies

5. Solaris

su: No shell/No directory! if sys is added to a users secondary group

Hi, When I include a user to the secondary group "sys" GID=3 in Solaris 9 OS I'm not able to login. I get these error. The user home directory and the shell exists. Is this because of any security hardening. # su - agent No directory! # su agent su: No shell # grep taddm /etc/passwd... (14 Replies)
Discussion started by: agent001
14 Replies

6. Solaris

#1 added to directory on rmount DVD drive

Currently have an issue were we use a script to load a security .dat key. The script was failing to load stating "Unable to open directory". I ssh'd into the server and performed an ls -la on the /cdrom directory. I show the usual cdrom0 but the directory on the cd should be key but is showing... (0 Replies)
Discussion started by: hypp1e
0 Replies

7. Shell Programming and Scripting

How to determine if there's a file in directory!

Hi All, I'm just wondering how can i determined if there's a file in directory and put it in a logs? dir="/home/test/" Please advise, Thanks, Use code tags, thanks. (1 Reply)
Discussion started by: nikki1200
1 Replies

8. Shell Programming and Scripting

Using filename to determine a prefix that needs to be added to string column on file?

Possible filenames: CDD_Whatever.txt DDD_Whatever.txt If the file prefix = CDD, I'd like to prefix every person ID (second column in my examples below) on the file with "c-" If the file prefix = DDD, I'd like to prefix ever person ID with "d-" Input: Desired Output: Any help... (2 Replies)
Discussion started by: lrluis
2 Replies

9. Shell Programming and Scripting

How to select all files added to a directory in the past 5 mins (HP-UX)?

Hey everyone, I need to select all files that were added to a specific directory in the past 5 mins and copy them over to a different directory. I am using HP-UX OS which does not have support for amin, cmin, and mmin. B/c of this, I am creating a temp file and will use the find -newer command... (7 Replies)
Discussion started by: mattkoz
7 Replies

10. Shell Programming and Scripting

How to copy the two most recently added files to another directory - HP-UX?

Hello, I am attempting to find and copy the two most recently added files to a specific directory, that fit a specific format. I was able to find the command to list the two most recently added files in directory: ls -1t | head -n 2 The command lists the two files names in a vertical list,... (11 Replies)
Discussion started by: mattkoz
11 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 08:31 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy