01-09-2007
Count of files based on date?
Hi Friends,
Can anyone help me with this:
To get the count of files that are existing in a directory created on a perticular date like in the example (01/08) .(having same pattern for the filename)
ex:
FileName Creted Date
FILE001 01/08/2007
FILE005 01/06/2007
TXT003 01/08/2007
FILE005 01/08/2007
I need count i.e "2" (FILE001 and FILE005 created on 01/08)
I have used
ls -l | grep -c ^- It is retrieving all the files in the directory,
Thanks in advance
Sam
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LEARN ABOUT DEBIAN
bzgrep
BZGREP(1) General Commands Manual BZGREP(1)
NAME
bzgrep, bzfgrep, bzegrep - search possibly bzip2 compressed files for a regular expression
SYNOPSIS
bzgrep [ grep_options ] [ -e ] pattern filename...
bzegrep [ egrep_options ] [ -e ] pattern filename...
bzfgrep [ fgrep_options ] [ -e ] pattern filename...
DESCRIPTION
Bzgrep is used to invoke the grep on bzip2-compressed files. All options specified are passed directly to grep. If no file is specified,
then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to
grep.
If bzgrep is invoked as bzegrep or bzfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, bzgrep
uses it as the grep program to be invoked. For example:
for sh: GREP=fgrep bzgrep string files
for csh: (setenv GREP fgrep; bzgrep string files)
AUTHOR
Charles Levert (charles@comm.polymtl.ca). Adapted to bzip2 by Philippe Troin <phil@fifi.org> for Debian GNU/Linux.
SEE ALSO
grep(1), egrep(1), fgrep(1), bzdiff(1), bzmore(1), bzless(1), bzip2(1)
BZGREP(1)