01-03-2007
parse variable
I have a variable (it is a date actually -> 2007-01-03) which
would be passed in as parameter, what I want is to parse in and put
year, month, and day in separate variables, I have tried the following
but doesn't work
echo $dt | awk -F- '{print $1 $2 $3}' | read y m d
Thanks in advance
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CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week. (This is the default.)
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
BSD
June 6, 1993 BSD