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Full Discussion: awk: last occurance
Top Forums Shell Programming and Scripting awk: last occurance Post 302101513 by pondlife on Tuesday 2nd of January 2007 12:19:03 PM
Old 01-02-2007
Question awk: last occurance

Hi All,

I need to extract the last occurance of a pattern match. So far I've got the code below which extracts the first occurance. Any ideas how I can modify it so that it extracts the last?

Code:
BEGIN {}                        
{                               
   if (data[$2]++ == 0)         
      lines[++count] = $0       
}                               
END {                           
    for (i = 1; i <= count; i++)
        print lines[i]          
}

Thanks in advance,

p.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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