Sponsored Content
Full Discussion: Problem with Date validation
Top Forums Shell Programming and Scripting Problem with Date validation Post 302100005 by sumesh.abraham on Friday 15th of December 2006 09:53:04 AM
Old 12-15-2006
Problem with Date validation

Hi All,

I've to validate a date input for the format YYYYMMDD. The input should be of 8 digits with only numeric values.

I tried the following

Code:
echo $1 | grep '^[0-9]\{8}$/p'
if [ $? -eq 0 ]
then
 echo "Valid"
else
 echo "invalid"

I get the error,

Code:
grep: RE error 16: Bad number.

Any help will be appreciated.
Thanks,
Sumesh
sumesh.abraham
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date Validation again

I want a sample Date validation script using if loops. The script should first compare "year".If the year is lesser than the current year,It should go for "month" checking. I have the script that splits the date into year,month and date.I want only the checking part. My if loop checking is not... (4 Replies)
Discussion started by: dave_nithis
4 Replies

2. Shell Programming and Scripting

Date Validation:

Hi I have below file with 3 rd column as date ....i want to make 3 column to mm/dd/yyyy . in the below file 2 row date is like 1/23/1994 so i want to append '0' to month i,e. 01/23/1994 and in the 3 row date is like 6/4/1994 ---so i want this to 06/04/1994 Source:... (1 Reply)
Discussion started by: satyam_sat
1 Replies

3. Shell Programming and Scripting

Date Validation

the user have to input the date format in mmddmmhhyyyy (month,date,minutes,hour,year) i want a shell script to check whether the user has properly input in the above said manner. kindly advice (2 Replies)
Discussion started by: vkca
2 Replies

4. Shell Programming and Scripting

Date Validation in unix

I have a script which is take date as parameter sh abc.sh <2010-02-01> #!/sh/bin my_date=$1 #Here i want to two diffrent dates ## 3 Days before ##date14query=$mydate - 4 (it will be 2010-01-28) ##date24query=$mydate +4 (it will be 2010-01-05) #Please Help (3 Replies)
Discussion started by: pritish.sas
3 Replies

5. Shell Programming and Scripting

Date validation

Hi, I have a script which runs on specific sunday. If that script runs on the sunday i want to execute another script on following wednesday. I have a log for that server. My wednesday scripts needs to check the sunday run log timestamp and if it matches it should run. Please help. Thanks,... (1 Reply)
Discussion started by: Krrishv
1 Replies

6. Shell Programming and Scripting

Date validation

File contains below data,how to validate the date using awk command or any command. date formate is fixed as "YYYYMMDD" test1|20120405 test2|20121405 output should be: test1|20120405 Thanks (2 Replies)
Discussion started by: bmk
2 Replies

7. Programming

Date validation in mysql

Hi All, We need to create the custom function to pass the parameter is date.if it is valid return 1 else 0 return should be 1 select is_date('2012-09-17'); return should be 0 select is_date('2012-79-17'); Thanks (2 Replies)
Discussion started by: bmk
2 Replies

8. Shell Programming and Scripting

Validation of date from file name

I'm writing a shell script for cleanup of older files from various sub-directories inside a main directory The structure of directories is as below: Logs daily online archive weekly online archive... (1 Reply)
Discussion started by: asyed
1 Replies

9. UNIX for Dummies Questions & Answers

Date Validation not working

Hi Experts, I have a date validation script in that i will validate the date for a given format and search in the logs for that date. The script logic is very simple like below. Validate_Date() { is_valid=1 while do date_format=$(date "+$1") echo -e "Please enter the $2 date like... (6 Replies)
Discussion started by: senthil.ak
6 Replies

10. What is on Your Mind?

Date validation

Hi folks, I new to shell script . I want to know how to validate a String as valid date example: 20150712 ---> valid date 20160524-->valid 201605T12-->invalid date 12341234--->invalid date we need to valid string( yyyymmdd) to date in SunOS 5.10 please give some idea to validate... (9 Replies)
Discussion started by: srinadhreddy27
9 Replies
DATEINTERVAL.FORMAT(3)							 1						    DATEINTERVAL.FORMAT(3)

DateInterval::format - Formats the interval

SYNOPSIS
public string DateInterval::format (string $format) DESCRIPTION
Formats the interval. PARAMETERS
o $format - The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign ( %). +------------------+--------------------------------------+---+ |$format character | | | | | | | | | Description | | | | | | | | Example values | | | | | | +------------------+--------------------------------------+---+ | | | | | % | | | | | | | | | Literal % | | | | | | | | | | | | % | | | | | | | | | | | Y | | | | | | | | | Years, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03 | | | | | | | | | | | y | | | | | | | | | Years, numeric | | | | | | | | | | | | 1, 3 | | | | | | | | | | | M | | | | | | | | | Months, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03, 12 | | | | | | | | | | | m | | | | | | | | | Months, numeric | | | | | | | | | | | | 1, 3, 12 | | | | | | | | | | | D | | | | | | | | | Days, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03, 31 | | | | | | | | | | | d | | | | | | | | | Days, numeric | | | | | | | | | | | | 1, 3, 31 | | | | | | | | | | | a | | | | | | | | | Total number of days as a result of | | | | a DateTime::diff or (unknown) other- | | | | wise | | | | | | | | | | | | 4, 18, 8123 | | | | | | | | | | | H | | | | | | | | | Hours, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03, 23 | | | | | | | | | | | h | | | | | | | | | Hours, numeric | | | | | | | | | | | | 1, 3, 23 | | | | | | | | | | | I | | | | | | | | | Minutes, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03, 59 | | | | | | | | | | | i | | | | | | | | | Minutes, numeric | | | | | | | | | | | | 1, 3, 59 | | | | | | | | | | | S | | | | | | | | | Seconds, numeric, at least 2 digits | | | | with leading 0 | | | | | | | | | | | | 01, 03, 57 | | | | | | | | | | | s | | | | | | | | | Seconds, numeric | | | | | | | | | | | | 1, 3, 57 | | | | | | | | | | | R | | | | | | | | | Sign " -" when negative, " +" when | | | | positive | | | | | | | | | | | | -, + | | | | | | | | | | | r | | | | | | | | | Sign " -" when negative, empty when | | | | positive | | | | | | | | | | | | -, | | | | | | +------------------+--------------------------------------+---+ RETURN VALUES
Returns the formatted interval. NOTES
Note The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1 month and 1 day". EXAMPLES
Example #1 DateInterval example <?php $interval = new DateInterval('P2Y4DT6H8M'); echo $interval->format('%d days'); ?> The above example will output: 4 days Example #2 DateInterval and carry over points <?php $interval = new DateInterval('P32D'); echo $interval->format('%d days'); ?> The above example will output: 32 days Example #3 DateInterval and DateTime::diff with the %a and %d modifiers <?php $january = new DateTime('2010-01-01'); $february = new DateTime('2010-02-01'); $interval = $february->diff($january); // %a will output the total number of days. echo $interval->format('%a total days')." "; // While %d will only output the number of days not already covered by the // month. echo $interval->format('%m month, %d days'); ?> The above example will output: 31 total days 1 month, 0 days SEE ALSO
DateTime::diff. PHP Documentation Group DATEINTERVAL.FORMAT(3)
All times are GMT -4. The time now is 05:27 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy