I want a sample Date validation script using if loops.
The script should first compare "year".If the year is lesser than the current year,It should go for "month" checking.
I have the script that splits the date into year,month and date.I want only the checking part.
My if loop checking is not... (4 Replies)
Hi
I have below file with 3 rd column as date ....i want to make 3 column to mm/dd/yyyy .
in the below file 2 row date is like 1/23/1994 so i want to append '0'
to month i,e. 01/23/1994 and in the 3 row date is like 6/4/1994 ---so i want this to 06/04/1994
Source:... (1 Reply)
the user have to input the date format in mmddmmhhyyyy (month,date,minutes,hour,year)
i want a shell script to check whether the user has properly input in the above said manner.
kindly advice (2 Replies)
I have a script which is take date as parameter
sh abc.sh <2010-02-01>
#!/sh/bin
my_date=$1
#Here i want to two diffrent dates
## 3 Days before
##date14query=$mydate - 4 (it will be 2010-01-28)
##date24query=$mydate +4 (it will be 2010-01-05)
#Please Help (3 Replies)
Hi,
I have a script which runs on specific sunday. If that script runs on the sunday i want to execute another script on following wednesday.
I have a log for that server. My wednesday scripts needs to check the sunday run log timestamp and if it matches it should run. Please help.
Thanks,... (1 Reply)
File contains below data,how to validate the date using awk command or any command.
date formate is fixed as "YYYYMMDD"
test1|20120405
test2|20121405
output should be:
test1|20120405
Thanks (2 Replies)
Hi All,
We need to create the custom function to pass the parameter is date.if it is valid return 1 else 0
return should be 1
select is_date('2012-09-17');
return should be 0
select is_date('2012-79-17');
Thanks (2 Replies)
I'm writing a shell script for cleanup of older files from various sub-directories inside a main directory
The structure of directories is as below:
Logs
daily
online
archive
weekly
online
archive... (1 Reply)
Hi Experts,
I have a date validation script in that i will validate the date for a given format and search in the logs for that date. The script logic is very simple like below.
Validate_Date()
{
is_valid=1
while
do
date_format=$(date "+$1")
echo -e "Please enter the $2 date like... (6 Replies)
Hi folks,
I new to shell script .
I want to know how to validate a String as valid date
example:
20150712 ---> valid date
20160524-->valid
201605T12-->invalid date
12341234--->invalid date
we need to valid string( yyyymmdd) to date in SunOS 5.10
please give some idea to validate... (9 Replies)
Discussion started by: srinadhreddy27
9 Replies
LEARN ABOUT PHP
dateinterval.format
DATEINTERVAL.FORMAT(3) 1 DATEINTERVAL.FORMAT(3)DateInterval::format - Formats the interval
SYNOPSIS
public string DateInterval::format (string $format)
DESCRIPTION
Formats the interval.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
%).
+------------------+--------------------------------------+---+
|$format character | | |
| | | |
| | Description | |
| | | |
| | Example values | |
| | | |
+------------------+--------------------------------------+---+
| | | |
| % | | |
| | | |
| | Literal % | |
| | | |
| | | |
| | % | |
| | | |
| | | |
| Y | | |
| | | |
| | Years, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03 | |
| | | |
| | | |
| y | | |
| | | |
| | Years, numeric | |
| | | |
| | | |
| | 1, 3 | |
| | | |
| | | |
| M | | |
| | | |
| | Months, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 12 | |
| | | |
| | | |
| m | | |
| | | |
| | Months, numeric | |
| | | |
| | | |
| | 1, 3, 12 | |
| | | |
| | | |
| D | | |
| | | |
| | Days, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 31 | |
| | | |
| | | |
| d | | |
| | | |
| | Days, numeric | |
| | | |
| | | |
| | 1, 3, 31 | |
| | | |
| | | |
| a | | |
| | | |
| | Total number of days as a result of | |
| | a DateTime::diff or (unknown) other- | |
| | wise | |
| | | |
| | | |
| | 4, 18, 8123 | |
| | | |
| | | |
| H | | |
| | | |
| | Hours, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 23 | |
| | | |
| | | |
| h | | |
| | | |
| | Hours, numeric | |
| | | |
| | | |
| | 1, 3, 23 | |
| | | |
| | | |
| I | | |
| | | |
| | Minutes, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 59 | |
| | | |
| | | |
| i | | |
| | | |
| | Minutes, numeric | |
| | | |
| | | |
| | 1, 3, 59 | |
| | | |
| | | |
| S | | |
| | | |
| | Seconds, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 57 | |
| | | |
| | | |
| s | | |
| | | |
| | Seconds, numeric | |
| | | |
| | | |
| | 1, 3, 57 | |
| | | |
| | | |
| R | | |
| | | |
| | Sign " -" when negative, " +" when | |
| | positive | |
| | | |
| | | |
| | -, + | |
| | | |
| | | |
| r | | |
| | | |
| | Sign " -" when negative, empty when | |
| | positive | |
| | | |
| | | |
| | -, | |
| | | |
+------------------+--------------------------------------+---+
RETURN VALUES
Returns the formatted interval.
NOTES
Note
The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected
because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
month and 1 day".
EXAMPLES
Example #1
DateInterval example
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');
?>
The above example will output:
4 days
Example #2
DateInterval and carry over points
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d days');
?>
The above example will output:
32 days
Example #3
DateInterval and DateTime::diff with the %a and %d modifiers
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."
";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
The above example will output:
31 total days
1 month, 0 days
SEE ALSO
DateTime::diff.
PHP Documentation Group DATEINTERVAL.FORMAT(3)