Sponsored Content
Top Forums Shell Programming and Scripting Supress ' quotes in a select statement inside Shell Script Post 302099921 by silicate on Thursday 14th of December 2006 05:29:30 PM
Old 12-14-2006
forgive me, i don't know the answer, but what i think you meant to ask is "How to escape a single quote in ksh"

i was a little confused when i read your post the first time, i hope it helps clear it up for anyone else that might be able to help
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Pipe SQL select statement results to script

Hello I would like to perform a select from a oracle table and return those values to my shell script For example: site=head -1 $infile | cut -c1-15 | awk '{printf "s%", $0} sqlplus -s /nolog |& #Open pipe to sql select col1, col2, col3, col4 from oracle_table where col5 =... (6 Replies)
Discussion started by: houtakker
6 Replies

2. Windows & DOS: Issues & Discussions

Want to use the output of Select statement in Unix script

Hi, I have a UNIX script which calls SQL Select statement: Now i want to use the output of that select statement within my UNIX script so as to call different shell script depending upon the output of the select statement. Can anyone help me in this regard. TIA Akhil Goel (4 Replies)
Discussion started by: akhilgoel9
4 Replies

3. Shell Programming and Scripting

escaping double-quotes inside the script?

I'm having a strange problem with escaping double-quotes. I have a script that looks like this: #!/bin/bash for HOST in `cat $INFILE | grep -v ^#` do for VFILER in `some_command` do echo " " echo -e '\E The problem with ssh command... (3 Replies)
Discussion started by: GKnight
3 Replies

4. Shell Programming and Scripting

single quotes in awk statement

Hi, I have written a code to modify a string say, StringA=abc,def,ghi I need to change it to something like: StringB=This means abc='ABC', This mean def='DEF', This means ghi= 'GHI' StringB=$(echo $StringA | awk -F',' 'BEGIN { OFS="," } { for (i=1; i<=NF;i++) $i="This means... (2 Replies)
Discussion started by: tostay2003
2 Replies

5. Shell Programming and Scripting

How can i use single quotes for SQL command in shell script

Hi. please help me to write the following query in a shell script. the Query is :select no,salary from emp_info where name='$var_name' the following is my code. #! /bin/sh var_name=$1 sqlplus -s user/pwd@DB << EOF select no,salary from emp_info where name="'$var_name'";... (4 Replies)
Discussion started by: little_wonder
4 Replies

6. Shell Programming and Scripting

using SELECT sql statement in shell script

Hi there I have a database on a remote box and i have been using shell script to insert data into it for example, i could have a script that did this SN=123456 n=server1 m=x4140 sql="UPDATE main SET hostname='$n',model='$m' WHERE serial='$SN';" echo $sql |/usr/sfw/bin/mysql -h... (4 Replies)
Discussion started by: hcclnoodles
4 Replies

7. Shell Programming and Scripting

Automatically select records from several files and then run a C executable file inside the script

Dear list its my first post and i would like to greet everyone What i would like to do is select records 7 and 11 from each files in a folder then run an executable inside the script for the selected parameters. The file format is something like this 7 100 200 7 100 250 7 100 300 ... (1 Reply)
Discussion started by: Gtolis
1 Replies

8. Shell Programming and Scripting

How to call an sql script inside a while statement in KSH

Hi all, I'm trying to run an sql inside a loop which looks like this #!bin/ksh while IFS=, read var1 var2 do sqlplus -s ${USERNAME}/${PASSWORD}@${ORACLE_SID} << EOF insert into ${TABLE} ( appt_date ) values ( '${var1 }' ); ... (6 Replies)
Discussion started by: ryukishin_17
6 Replies

9. Shell Programming and Scripting

How to ignore delimiters inside the quotes?

Hi Experts, How to ignore any delimiters which is inside the quotes. in awk script. I am having script which counts number of delimiters from the line now i need count delimiters only separators . `grep "14" | cut -d"=" -f2` -F'~'if (NF-1 != v1) ' this command counts number of Tilde... (7 Replies)
Discussion started by: Ganesh Khandare
7 Replies

10. Shell Programming and Scripting

Supress java error output to shell

Hello, I know this isn't exactly a shell script question but I'm not sure where else to post it. I am running a java program out of a shell script. There are times when I get an error like, "java.lang.ArrayIndexOutOfBoundsException: 22 at blah, blah at blah, blah ... (3 Replies)
Discussion started by: LMHmedchem
3 Replies
LUA(1)							      General Commands Manual							    LUA(1)

NAME
lua - Lua interpreter SYNOPSIS
lua [ options ] [ script [ args ] ] DESCRIPTION
lua is the stand-alone Lua interpreter. It loads and executes Lua programs, either in textual source form or in precompiled binary form. (Precompiled binaries are output by luac, the Lua compiler.) lua can be used as a batch interpreter and also interactively. The given options (see below) are executed and then the Lua program in file script is loaded and executed. The given args are available to script as strings in a global table named arg. If these arguments contain spaces or other characters special to the shell, then they should be quoted (but note that the quotes will be removed by the shell). The arguments in arg start at 0, which contains the string `script'. The index of the last argument is stored in arg.n. The arguments given in the command line before script, including the name of the interpreter, are available in negative indices in arg. At the very start, before even handling the command line, lua executes the contents of the environment variable LUA_INIT, if it is defined. If the value of LUA_INIT is of the form `@filename', then filename is executed. Otherwise, the string is assumed to be a Lua statement and is executed. Options start with - and are described below. You can use -- to signal the end of options. If no arguments are given, then -v -i is assumed when the standard input is a terminal; otherwise, - is assumed. In interactive mode, lua prompts the user, reads lines from the standard input, and executes them as they are read. If a line does not contain a complete statement, then a secondary prompt is displayed and lines are read until a complete statement is formed or a syntax error is found. So, one way to interrupt the reading of an incomplete statement is to force a syntax error: adding a `;' in the middle of a statement is a sure way of forcing a syntax error (except inside multiline strings and comments; these must be closed explicitly). If a line starts with `=', then lua displays the values of all the expressions in the remainder of the line. The expressions must be separated by commas. The primary prompt is the value of the global variable _PROMPT, if this value is a string; otherwise, the default prompt is used. Similarly, the secondary prompt is the value of the global variable _PROMPT2. So, to change the prompts, set the corresponding variable to a string of your choice. You can do that after calling the interpreter or on the command line with _PROMPT='lua: ', for exam- ple. (Note the need for quotes, because the string contains a space.) The default prompts are ``> '' and ``>> ''. OPTIONS
- load and execute the standard input as a file, that is, not interactively, even when the standard input is a terminal. -e stat execute statement stat. You need to quote stat if it contains spaces, quotes, or other characters special to the shell. -i enter interactive mode after script is executed. -l file call require(file) before executing script. Typically used to load libraries (hence the letter l). -v show version information. -P suppress the creation of a standard LUA_PATH variable. Use this if you need to run scripts which conflict with system-installed libraries. SEE ALSO
luac(1) http://www.lua.org/ DIAGNOSTICS
Error messages should be self explanatory. AUTHORS
R. Ierusalimschy, L. H. de Figueiredo, and W. Celes <lua@tecgraf.puc-rio.br> Debian modifications to the manpage by Daniel Silverstone <dsilvers@debian.org> 2003/04/02 00:05:20 LUA(1)
All times are GMT -4. The time now is 04:38 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy