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Full Discussion: Date comparison
Top Forums Shell Programming and Scripting Date comparison Post 302099615 by sumesh.abraham on Wednesday 13th of December 2006 07:15:33 AM
Old 12-13-2006
Date comparison

Hi all,

I've a shell script which runs on Bourne shell. I've to do a date comparison. If the value of the supplied parameter(in format YYYYMMDD)is greater than todays's date(format YYYYMMDD), it should prompt the user that the supplied date is greater than today's date. The script is given below.

Code:
#! /bin/sh
dateval=`date +%Y%m%d`
if [ $# -eq 0 ]
then
dateval=`date +%Y%m%d`
elif [ $1 -gt $dateval ];then
echo "Supplied date is greater than current date"
else
 dateval=$1
fi

The script gives the desired result.But, is there any other alternative to using 'gt' other than DateCalc function.

Any help will be appreciated.
Thanks,
Sumesh
sumesh.abraham
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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