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Top Forums Shell Programming and Scripting Problem when passing argument to a shell script Post 302099599 by vino on Wednesday 13th of December 2006 04:56:25 AM
Old 12-13-2006
Please use code tags when you are posting some code. I put your code within the tags.

In your script, the value of $dateval is not initialized in elif [ $dateval -gt date ];then. and hence you cant test it against date.

And how can you compare dates with the -gt construct ?

And what is date in that same line. Did you mean $date ?

Try this.
Code:
#! /bin/sh

if [ $# -eq 0 ] ; then
  dateval=`date`
else
  dateval=$1
fi
echo $dateval


Last edited by vino; 12-13-2006 at 06:01 AM..
 

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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)
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