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Top Forums UNIX for Advanced & Expert Users problem with redirect stdout to file Post 302098713 by mlucas on Wednesday 6th of December 2006 06:31:05 AM
Old 12-06-2006
Quote:
Originally Posted by vino
We ran into the same problem the other day in one of our scripts.

You need to change your $fname to ${fname}

Look at this script to see the behaviour.

Code:
[/tmp]$ cat try.sh
#! /bin/sh

a=12
b=34
echo $a_$b
echo ${a}_$b
[/tmp]$ sh try.sh
34
12_34
[tmp]$

Hi thanks that did the trick.

Do you know why this is the case ?? I have used the $fname in loads of scripts before with out having to use the {}
 

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ZIP_SOURCE_FILE(3)					     Library Functions Manual						ZIP_SOURCE_FILE(3)

NAME
zip_source_file - create data source from a file LIBRARY
libzip (-lzip) SYNOPSIS
struct zip_source * zip_source_file(struct zip *archive, const char *fname); "zip_uint64_t start" "zip_int64_t len" DESCRIPTION
The function zip_source_file creates a zip source from a file. zip_source_file opens fname and reads len bytes from offset start from it. If len is 0 or -1, the whole file (starting from start ) is used. The fie is opened and read when the data from the source is used, usually by zip_close. RETURN VALUES
Upon successful completion, the created source is returned. Otherwise, NULL is returned and the error code in archive is set to indicate the error. ERRORS
zip_source_file fails if: [ZIP_ER_INVAL] fname, start, or len are invalid. [ZIP_ER_MEMORY] Required memory could not be allocated. [ZIP_ER_OPEN] Opening fname failed. SEE ALSO
libzip(3), zip_add(3), zip_replace(3), zip_source_buffer(3), zip_source_filep(3), zip_source_free(3), zip_source_function(3), zip_source_zip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH August 1, 2008 ZIP_SOURCE_FILE(3)
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