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Full Discussion: Unix Korn Shell Array Issue (SunOS)
Top Forums Shell Programming and Scripting Unix Korn Shell Array Issue (SunOS) Post 302096948 by Janus on Monday 20th of November 2006 08:19:11 PM
Old 11-20-2006
Andrek, I put in your code and it executed to work great! I went one step further and added the following piece to list out any existing directories and it's corresponding files:

if [ -d ${lsarry[$start]} ]
then
echo "-${lsarry[$start]}- is a directory"
cd ${lsarry[$start]}
ls -l
else

I do have one more question however. As someone always learning in the Unix Scripting field, I was wondering if you could explain what a few of the expressions are doing?

lslist="`ls -m | tr -d \",\"`"
set -A lsarry $lslist
start=1
while [ $start -lt ${#lsarry[*]} ] This is where I get confused. I understand that you are asking if the index is less than the value in the array, but what does the # before the lsarry mean? I take it that the[*] means the last array slot to contain a value?
do
if [ -d ${lsarry[$start]} ] I'm unfamiliar with -d before the array. Does this mean "IF 'D' = ArrayValue?" How is the code being interpreted?
then
echo "-${lsarry[$start]}- is a directory"
cd ${lsarry[$start]}
ls -l
else
echo "-${lsarry[$start]}- is not a directory"
fi
start=`expr $start + 1`
done

Everything after the first two questions in italics I understand, if you could explain those two just a little bit more, it would be greatly appreciated. Thanks!
 

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