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Top Forums UNIX for Dummies Questions & Answers to check if a string has only digits Post 302096438 by Andrek on Wednesday 15th of November 2006 04:24:25 PM
Old 11-15-2006
Try this

#!/bin/sh
if [ -z "`echo \"$1\" | tr -d \"[:alnum:]\"`" ]
then
echo "True - only alpha and numeric"
else
echo "False - there are NON alpha and numeric stuff here!"
fi
 

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CheckDigits::M11_013(3pm)				User Contributed Perl Documentation				 CheckDigits::M11_013(3pm)

NAME
CheckDigits::M11_013 - compute check digits for VAT Registration Number (GR) SYNOPSIS
use Algorithm::CheckDigits; $ustid = CheckDigits('ustid_gr'); if ($ustid->is_valid('123456783')) { # do something } $cn = $ustid->complete('12345678'); # $cn = '123456783' $cd = $ustid->checkdigit('123456783'); # $cd = '3' $bn = $ustid->basenumber('123456783'); # $bn = '12345678'; DESCRIPTION
ALGORITHM 1. Beginning right with the digit before the checkdigit all digits are weighted with 2 ** position. I. e. the last digit is multiplied with 2, the next with 4, then 8 and so on. 2. The weighted digits are added. 3. The sum from step 2 is taken modulo 11. 4. If the sum from step 3 is greater than 9, the check sum is 0 else it is the sum itself. METHODS is_valid($number) Returns true only if $number consists solely of numbers and hyphens and the two digits in the middle are valid check digits according to the algorithm given above. Returns false otherwise, complete($number) The check digit for $number is computed and inserted into the middle of $number. Returns the complete number with check digit or '' if $number does not consist solely of digits, hyphens and spaces. basenumber($number) Returns the basenumber of $number if $number has a valid check digit. Return '' otherwise. checkdigit($number) Returns the check digits of $number if $number has valid check digits. Return '' otherwise. EXPORT None by default. AUTHOR
Mathias Weidner, <mathias@weidner.in-bad-schmiedeberg.de> SEE ALSO
perl, CheckDigits, www.pruefziffernberechnung.de, perl v5.10.0 2008-05-17 CheckDigits::M11_013(3pm)
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