11-14-2006
select last field from a file
hi everybody
i would to select the last field of a file
here as you can see i select the field number 8
y=`cat sortie2 | grep "^[1-9999]"| grep "starting"| awk '{ print $8}'`
but line can containt more or less field in never know, i just know is the last one
so i wondering to know if is something like
y=`cat sortie2 | grep "^[1-9999]"| grep "starting"| awk '{ print $lastfield}'`
or a other solution
thank a lot
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ZGREP(1) BSD General Commands Manual ZGREP(1)
NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)
AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD
December 28, 2003 BSD