11-09-2006
accessing variables declared in another perl script
Hi all,
I have a perl script which declares two variables and calls another perl script which accesses those variables. But I am unable to access the variables in the called script. My script is as follows:
my $ENV{a}="20";
system("perl called.pl");
and my called.pl contains:
print "$ENV{a}\n";
My problem is that a variable declaration script reads the values from a config file and then I calll that variable declaration script from my main script which access the variables. I am declaring all the variables as Environment variables.
Please help me.
Thanks,
guru
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LEARN ABOUT CENTOS
makesh
MAKESH(1) General Commands Manual MAKESH(1)
NAME
makeSH - a .SH script maker
SYNOPSIS
makeSH files
DESCRIPTION
MakeSH examines one or more scripts and produces a .SH file that, when run under sh, will produce the original script. The .SH script so
produced has two sections containing code destined for the output. The first section has variable substitutions performed on it (taking
values from config.sh), while the second section does not. MakeSH does not know which variables you want to have substituted, so it puts
the whole script into the second section. It's up to you to insert any variable substitutions in the first section for any values you want
from config.sh.
You should run makeSH from within your top-level directory and use the relative path to the file as an argument, so that the "Extracting
..." line printed while running the produced .SH file later on will give that same path.
AUTHOR
Larry Wall <lwall@netlabs.com>
SEE ALSO
pat(1), metaconfig(1), makedist(1).
BUGS
It could assume that variables from metaconfig's Glossary need to be initialized in the first section, but I'm too lazy to make it do that.
LOCAL MAKESH(1)