11-01-2006
what left of the pattern
I have a script which loop through a directory then report any file matches the given pattern,
say, the pattern is "a2006", this file would be returned
a20061101.txt
I would like to know how can I get the remaining of the filename, so
a20061101txt - a2006 = 1101.txt
Can anybody help? Thank you so much!
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LEARN ABOUT REDHAT
exigrep
EXIGREP(8) System Manager's Manual EXIGREP(8)
NAME
EXIGREP - Search Exim's main log
SYNOPSIS
exigrep [-l] pattern [log file] ...
DESCRIPTION
The exigrep utility is a Perl script that searches one or more main log files for entries that match a given pattern. When it finds a
match, it extracts all the log entries for the relevant message, not just those that match the pattern. Thus, exigrep can extract complete
log entries for a given message, or all mail for a given user, or for a given host, for example.
The -l flag means 'literal', that is, treat all characters in the pattern as standing for themselves. Otherwise the pattern must be a Perl
regular expression. The pattern match is case-insensitive. If no file names are given on the command line, the standard input is read.
If the location of a zcat command is known from the definition of ZCAT_COMMAND in Local/Makefile, exigrep automatically passes any file
whose name ends in COMPRESS_SUFFIX through zcat as it searches it.
BUGS
This manual page needs a major re-work. If somebody knows better groff than us and has more experience in writing manual pages, any patches
would be greatly appreciated.
SEE ALSO
exim(8), perlre(1), /usr/share/doc/exim4-base/
AUTHOR
This manual page was stitched together from spec.txt by Andreas Metzler <ametzler at downhill.at.eu.org>, for the Debian GNU/Linux system
(but may be used by others).
March 26, 2003 EXIGREP(8)