find `pwd` -type d | grep TESTINGDIR 2> dirList.txt
With the above command, you are not redirecting standard output to dirlist.txt, its telling shell to redirect any errors(fd2) to dirlist.txt and standard output is redirected no where, therefor you are getting output echoed back at your screen, change your command as follows:
and see what you get.
Hey there, I'm a total newbie unix guy here and just picking this stuff up. Have a very small script I put together that works fine from the command line but not once I put it in a cron job. Searched and found this thread and am wondering it it has something to do with setting variables, though the... (7 Replies)
i would like to make a shell script (red hat 9 cmd line only)
to telnet to my local isp's webmail server on port 25 and send it commands
such as helo :) help would be much appreciated, and i found no posts similar that answered my question... the closest i've gotten to an answer from about 8... (3 Replies)
Hi all-
I'm trying to search through some .gz log files to verify certain feeds have passed through our app.
I have a small script that I wrote in hopes that I could automate the checking but haven't been able to get the zgrep to work. When I copy it to the command line directly it works... (2 Replies)
When I run this code from the command line works
spinel.middlebury.edu:/u02/sct/banner/bandev2/middlebury/shl:DEV2$ ls ef*
eftseq.dat
spinel.middlebury.edu:/u02/sct/banner/bandev2/middlebury/shl:DEV2$ file_seq=$( < eftseq.dat) ... (1 Reply)
/usr/bin/find $SEARCH_DIR -daystart \( \( -name 'KI*' -a -name '*.csv' \) -o -name '*_xyz_*' \) -mtime $DAYS_AGO -printf %f -printf "\n" | sort -r > $FILES
The above command gives different results when run on a cron job. When run manually the result is accurate. (2 Replies)
Hi all .... vexing problem here ...
I am using sed to replace some special characters in a .txt file:
sed -e 's/_<ED>_/_355_/g;s/_<F3>_/_363_/g;s/_<E1>_/_341_/g' filename.txt
This command replaces <ED> with í , <F3> with ó and <E1> with á.
When I run the command to standard output, it works... (1 Reply)
Hey guys. Hopefully this is an easy one but having reference similar problems on the web I still can't fix it.
I am doing a recursive find and replace from a script. Of course I could just run the damn thing from the command line but it's bugging me now and want to get it working.
grep -rl... (4 Replies)
OK , ..
This is an odd one. I have a new server and I need to have a tunnel open to it.
I have this exact process running on a few others but this new one I just got is not allowing the script to connect.
I set up my users account and ssh keys
from the server that will host the tunneling i... (6 Replies)
Hi All,
This command works when I type it on but when I run the batch file it doesn't..any ideas why?
attrib.exe * | find /c /v "" >filecount.txt (1 Reply)
OSX 10.9
I am building a script that evaluates the difference between 2 files. Here is a command that does not work transparently.
Running this command in Terminal yields great results; however when I put that line in a .sh script, I get the errors shown below. Am I doing something silly?
... (1 Reply)
Discussion started by: sudo
1 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)