Hi,
I have written one script to calculate total space of all file in one directory, ignoring subdirectory, it works fine.
Now, I've been trying to calculate all files which includes files in any subdirectories.
I use recursive function to do this, but it can work only if there is only one... (4 Replies)
Hi,
After checking all the UNIX threads, I am able to come up with a solution so far. I am working on a shell script where it moves the files to a certain directory. The conditions to check are
1) Check if the file exists in the current directory.
2) Check if the destination directory... (2 Replies)
I am trying to move file created/modified in 2008 year to <new directory>. But trapped badly in Xargs {}.
Looks like mv is not getting destination file properly. It assumes source file s to be destination directory n gives me erroir. "Target must be a directory"
Run-
#/home/mktrisk: find... (4 Replies)
Hi,
We currently have an Oracle database running and it is creating lots of processes in the /proc directory that are 1000M in size. The size of the /proc directory is now reading 26T. How can this be if the root file system is only 13GB?
I have seen this before we an Oracle temp file... (6 Replies)
To find the whole size of a particular directory i use "du -sk /dirname".. but after finding the direcory's size how do i make conditions like if the size of the dir is more than 1 GB i hav to delete some of the files inside the dir (0 Replies)
Hello :
I need some help in writing a ksh script which will find a particular directory in all the file systems in a server and finally report the total size of the direcotry in all the file systems.
Some thing like this..
find /u*/app/oracle -type d -name "product" -prune
and then... (1 Reply)
Hi,
Can I find size of the file from size of the buffer written?
nbECRITS = fwrite(strstr(data->buffer, ";") + 1, sizeof(char), (data->buffsize) - LEN_NOM_FIC, fic_sortie);
Thank You :) (1 Reply)
I have been searching both on Unix.com and Google and have not been able to find the answer to my question. I think it is partly because I can't come up with the right search terms.
Recently, my virtual server switched storage devices and I think the problem may be related to that change.... (2 Replies)
Discussion started by: jmgibby
2 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)