09-19-2006
store awk results in a variable
I try to get the month (of last save) and the filename into a variable, is this possible ?
something like this :
for month in `ls -la | awk '{print $6}'`
do
if [[ $month == "Sep" ]]
then
a=filename of the matching file
cp $a /Sep
fi
thanks,
Steffen
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I have the results of a grep with -n store in a shell variable
ie
VAR=`grep -n -e 'PATTERN' file`
How ever I am missing the line breaks in the variable , How do I store the resualts of grep with many lines in to a variables. I want the varable should be the sawmway as we do the grep
grep... (3 Replies)
Discussion started by: jojan
3 Replies
2. UNIX for Dummies Questions & Answers
Hello,
I have a question regarding the awk command. Here is the line I need to grep:
1 F= -.13250138E+03 E0= -.13249556E+03 d E =-.174650E-01 mag= 35.2157
Instead of displaying the number in red I would like to store it as a variable such as X. Is there a way to do this? Thanks for any... (3 Replies)
Discussion started by: modey3
3 Replies
3. UNIX for Dummies Questions & Answers
Hello Guys...
I want a small help from you guys.
Actually in Oracle, we are having a utlity called spool through which can store whatever SQL statements executed and other queries and the output of those queries in a file
So, similarly in Unix, if I start a session executing a number of Unix... (2 Replies)
Discussion started by: mraghunandanan
2 Replies
4. Shell Programming and Scripting
Hi Perl Gurus , need URGENT HELP PLEASE !!!!!
I have one recursive Perl function which takes path of any directory as argument and returns array containing all the sub folders inside it recursively.
Now the problem is that it works well if i use it with one time but the problem is that when... (0 Replies)
Discussion started by: anthriksh2000
0 Replies
5. Shell Programming and Scripting
Hi ,
Here is my script
echo 'Enter MSISDN for the Calling Number'
read ms
acc=`sqlplus -s testing/testing123@BP_$ARBORENV<<EOF
set heading off;
set feedback off;
select external_id from external_id_equip_map where subscr_no = (select subscr_no from external_id_equip_map where account_no =... (1 Reply)
Discussion started by: Pratik4891
1 Replies
6. Shell Programming and Scripting
Hi,
I want to store the results of running ls in a directory on a remote host using ftp.
For example,
#!/usr/bin/ksh
ftp -n hostx <<EOF
user username password
ls /tmp/RandomFiles.*
#I need to put the results of that ls command into some file, so I can get the last file in... (3 Replies)
Discussion started by: mrskittles99
3 Replies
7. Shell Programming and Scripting
Hi,
I have a script where I make a sqlplus connection. In the script I have multiple sql queries within that sqlplus connection. I want the result of the queries to be stored in shell variables declared earlier. I dont want to use procedures. Is there anyway else.
Thanks in advance..
Cheers (6 Replies)
Discussion started by: gonchusirsa
6 Replies
8. Shell Programming and Scripting
Hello everyone,
I have a shell script, which connects to the database and runs .sql file.
after executing of .sql file, i need to store the results in error table.
How can i achieve this one? could you please give your suggestions.
here is my code.
#!/bin/sh
#set -vx
SCHEMA_NAME=$1... (1 Reply)
Discussion started by: Rami Reddy
1 Replies
9. Shell Programming and Scripting
So, I've been playing with speeding up some analysis we do by using multiple threads of awk (actually, mawk, but code-compatible as far as I use it) on multiple CPU cores. So, I have a big data file and I have several copies of exactly the same processor script, written in mawk. I also have a... (8 Replies)
Discussion started by: treesloth
8 Replies
10. Shell Programming and Scripting
Good morning all,
This is the file name in question OD_Orders_2019-02-19.csv
I am trying to create a bash script to read into files with yesterdays date on the file name while retaining the rest of the files name. I would like for $y to equal, the name of the file with a formula output with... (2 Replies)
Discussion started by: Ibrahim A
2 Replies
CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-3hjry] [-A after] [-B before] [-d day-of-week] [-R reform-spec] [[month] year]
DESCRIPTION
cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-3 Same as ``-A 1 -B 1''.
-A after
Display after months after the specified month.
-B before
Display before months before the specified month.
-d day-of-week
Specifies the day of the week on which the calendar should start. Valid values are 0 through 6, presenting Sunday through Saturday,
inclusively. The default output starts on Sundays.
-h Highlight the current day, if present in the displayed calendar. If output is to a terminal, then the appropriate terminal sequences
are used, otherwise overstriking is used. If more than one -h is used and output is to a terminal, the current date will be high-
lighted in inverse video instead of bold.
-j Display Julian dates (days one-based, numbered from January 1).
-R reform-spec
Selects an alternate Gregorian reform point from the default of September 3rd, 1752. The reform-spec can be selected by one of the
built-in names (see NOTES for a list) or by a date of the form YYYY/MM/DD. The date and month may be omitted, provided that what is
specified uniquely selects a given built-in reform point. If an exact date is specified, then that date is taken to be the first
missing date of the Gregorian Reform to be applied.
-r Display the month in which the Gregorian Reform adjustment was applied, if no other month or year information is given. If used in
conjunction with -y, then the entire year is displayed.
-y Display a calendar for the current year.
If no parameters are specified, the current month's calendar is displayed. A single parameter specifies the year and optionally the month in
ISO format: ``cal 2007-12'' Two parameters denote the month (1 - 12) and year. Note that the century must be included in the year.
A year starts on Jan 1.
NOTES
In the USA and Great Britain the Gregorian Reformation occurred in 1752. By this time, most countries had recognized the reformation
(although a few did not recognize it until the 1900's.) Eleven days following September 2, 1752 were eliminated by the reformation, so the
calendar for that month is a bit unusual.
In view of the chaotic way the Gregorian calendar was adopted throughout the world in the years between 1582 and 1928 make sure to take into
account the date of the Gregorian Reformation in your region if you are checking a calendar for a very old date.
cal has a decent built-in list of Gregorian Reform dates and the names of the countries where the reform was adopted:
Italy Oct. 5, 1582 Denmark Feb. 19, 1700
Spain Oct. 5, 1582 Great Britain Sep. 3, 1752
Portugal Oct. 5, 1582 Sweden Feb. 18, 1753
Poland Oct. 5, 1582 Finland Feb. 18, 1753
France Dec. 12, 1582 Japan Dec. 20, 1872
Luxembourg Dec. 22, 1582 China Nov. 7, 1911
Netherlands Dec. 22, 1582 Bulgaria Apr. 1, 1916
Bavaria Oct. 6, 1583 U.S.S.R. Feb. 1, 1918
Austria Jan. 7, 1584 Serbia Jan. 19, 1919
Switzerland Jan. 12, 1584 Romania Jan. 19, 1919
Hungary Oct. 22, 1587 Greece Mar. 10, 1924
Germany Feb. 19, 1700 Turkey Dec. 19, 1925
Norway Feb. 19, 1700 Egypt Sep. 18, 1928
The country known as Great Britain can also be referred to as England since that has less letters and no spaces in it. This is meant only as
a measure of expediency, not as a possible slight to anyone involved.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
BSD
December 21, 2007 BSD