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Top Forums Shell Programming and Scripting Bourne Shell script - log for users loggin on and off Post 302088047 by noodlesoup on Friday 8th of September 2006 07:02:30 AM
Old 09-08-2006
OK, this is what I have got now, not srue where I have gone wrong. it says I have a syntax error on line 30; ';;' unexpected? any ideas? I thought these were needed for the case to work

PHP Code:
#! /bin/sh

echo "The current users are:"

who awk '{print $1}' sort temp1
cp temp1 temp2
more temp1

while true
do
    
who awk '{print $1}' sort temp2
    cmp 
-s temp1 temp2

    
case "$?" in
    
    0
)
        echo 
"No user has logged in/out in the last 5 seconds."
        
;;
    
    
1)
        
user=`comm -23 temp1 temp2`
        
file=`grep $user temp1 temp2 | cut -c 1-5`

        if [ 
$file "temp1" ]
            echo 
"User "$user" has logged out."
            
        
        
if [ $file "temp2" ]
            echo 
"User "$user" has logged in."
        
;;
        
    
esac
    
    rm temp1
    mv temp2 temp1
    
    sleep 5

done 
 

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