08-28-2006
How to cut last 10 digits off
Hi I'm new to this. I need to cut off the last 10 digits from a line.
I've used awk {'print $4'} filename.txt | cut -c 32-42 but this does not guarantee only the last 10 characters.
Please help. Thanks.
Sara
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CUT(1) General Commands Manual CUT(1)
NAME
cut - select out columns of a file
SYNOPSIS
cut [ -b | -c] list [file...]
cut -f list [-d delim] [ -s]
OPTIONS
-b Cut specified bytes
-c Select out specific characters
-d Change the column delimiter to delim
-f Select out specific fields that are separated by the
-i Runs of delimiters count as one
-s Suppres lines with no delimiter characters, when used
EXAMPLES
cut -f 2 file # Extract field 2
cut -c 1-2,5 file # Extract character columns 1, 2, and 5
cut -c 1-5,7- file # Extract all columns except 6
DESCRIPTION
[file...]" delimiter character ( see delim)" with the -f option. Lines with no delimiters are passwd through untouched"
Cut extracts one or more fields or columns from a file and writes them on standard output. If the -f flag is used, the fields are sepa-
rated by a delimiter character, normally a tab, but can be changed using the -d flag. If the -c flag is used, specific columns can be
specified. The list can be comma or BLANK separated. The -f and -c flags are mutually exclusive. Note: The POSIX1003.2 standard requires
the option -b to cut out specific bytes in a file. It is intended for systems with multi byte characters (e.g. kanji), since MINIX uses
only one byte characters, this option is equivalent to -c. For the same reason, the option -n has no effect and is not listed in this man-
ual page.
SEE ALSO
sed(1), awk(9).
CUT(1)