Hello,
plz help me out with this error,
i am getting this error when i compile my code with gcc.
/usr/lib/gcc-lib/i386-redhat-linux/3.3.2/../../../crt1.o(.text+0x18): In function `_start':
: undefined reference to `main'
/tmp/cciLxqdV.o(.text+0x3c): In function `HandleUserTransaction()':... (2 Replies)
My input text has the following pattens:
func_a(3,
4,
5);
I want to replace it with this:
func_b(3,
4,
5,
6);
I'm trying the following expression, but it does not work:
perl -p -e "s/func_a\((.*)?\);/func_b(\1,\n6)/s" <... (8 Replies)
Here is the question...
Create a new script, sub2, taking three parameters...
1.) the string to be replaced
2.) the string with which to replace it
3.) the name of the file in which to make the substitution
...that treats the string to be replaced as plain text instead of as a regular... (1 Reply)
Guys,
May i know how can we de reference the code reference variable.?
my $a = sub{$a=shift;$b=shift;print "SUM:",($a+$b),"\n";};
print $a->(4,5);
How can we print the whole function ?
Please suggest me regarding this.
Thanks for your time :)
Cheers,
Ranga :) (0 Replies)
Hello all,
I am using sed to parse a particular part of a string and am having problems. I am getting the following error:
sed: -e expression #1, char 28: invalid reference \1 on `s' command's RHS
Here is the code I am using:
echo "Alarm SET:"
echo ""
echo "Date: " $DATE
echo... (4 Replies)
I was trying to compile the following code in cygwin using g++:
------------------------------------------
#include <iostream>
using namespace std;
int identity(int input)
{
int output = input;
return output;
}
------------------------------------------
I get this error:
... (7 Replies)
I am trying to change a single line of a special file whose comment character is ! to show a path to the file in the comment. such as:
!!HFSS and mcm path: \Signal_Integrity\Package_SI\Section_Models\C4toTrace\28nm\D6HS\SLC_5-2-5\GZ41_ICZ\NSSS\
to a different path and replace the !!HFSS... (1 Reply)
i have a text
20 21 22 23 24 25 26
i want to get 22 using sed back reference.
I have used sed 's/{6}\(..\).*/\1/'
but, it does not work.
I am missing something somewhere.
Please help. (5 Replies)
I have data that looks like this:
<Country code="US"><tag>adsf</tag><tag>bdfs</tag></Country><Country code="CA"><tag>asdf</tag><tag>bsdf</tag></Country>
I want to grab the country code save it, then drop each new "<..." onto a new line with the country code added to the beginning of each
So,... (9 Replies)
Discussion started by: JenniferAmon
9 Replies
LEARN ABOUT CENTOS
rpmdev-bumpspec
RPMDEV-BUMPSPEC(1) User Commands RPMDEV-BUMPSPEC(1)NAME
rpmdev-bumpspec - manual page for rpmdev-bumpspec version 1.0.11
SYNOPSIS
rpmdev-bumpspec [OPTION]... SPECFILE...
DESCRIPTION
rpmdev-bumpspec bumps release tags in specfiles.
OPTIONS -h, --help
show this help message and exit
-c COMMENT, --comment=COMMENT
changelog comment (default: "- rebuilt")
-u USERSTRING, --userstring=USERSTRING
user name+email string (default: output from rpmdev-packager(1))
-r, --rightmost
bump trailing .<DIGIT> component if found, append .1 if not; no-op if -s is specified
-s STRING, --string=STRING
bump trailing .STRING<DIGIT> component if found, append .STRING1 if not; trumps -r
-V, --verbose
more output
-v, --version
output version number and exit
COPYRIGHT
Copyright (C) 2005-2010 Fedora Project This program is free software; you can redistribute it and/or modify it under the terms of the GNU
General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later ver-
sion.
rpmdev-bumpspec version 1.0.11 June 2014 RPMDEV-BUMPSPEC(1)