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Full Discussion: Select ALL in VI Editor
Top Forums UNIX for Dummies Questions & Answers Select ALL in VI Editor Post 302084826 by patras on Monday 14th of August 2006 03:47:38 AM
Old 08-14-2006
Thanks for your reply.
Quote:
1. You can do <n>,$y in the command mode where n is the number of line and $ represents end of file. e.g. :15,$y
What about if I don't know the line number? Is there a way in vi to show the line number with each line? And what would be the command to copy lines from any line to begining of file ie 1st line?
Quote:
2. you can just enter the line number in command mode. e.g. :20 with place the cursor at line 20.
That works fine.
Quote:
3. You can always do a set nu in command mode and check it.
Can you pls give me example of this?
Quote:
4. Do a !<command name> in escape mode.
Yeah, that worked for me
Quote:
5. Can you eloborate more on what you want.
Suppose I want add a line "Test Line" after line number 11, without opening vi, is it possible?

Thanks in advance for any reply.

Cheers,
Patras
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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