08-10-2006
thanks tmarkle for ur help.... thanks alot
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1. Shell Programming and Scripting
how can i show the value when i divide a number where the dividend is greater then the divisor. for example...
3 divided by 15 ---> let x=3/15
when i do this in the shell environment it gives me an output of 0.
please help me.
thanks. (3 Replies)
Discussion started by: inquirer
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2. Filesystems, Disks and Memory
I have a doubt with an error message, and i want to be sure if this is a normal situation or not.
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3. Shell Programming and Scripting
Hi,
I am writing a script that among other things will be checking for various files on mount points. One of the conditions is that unless the server has failed over the df command will show root ( / ). If when checking the files the script comes across /, I want it to skip it, otherwise to... (2 Replies)
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4. Shell Programming and Scripting
i have a script that is doing the following:
awk 'BEGIN {FS=","} ; {printf("%.10f",($5 - $2)/(3 * $3))}' data > test
now some records in $3 contain zeroes. i don't want to remove those records. is it possible to check for division by zero and then write a "N/A" for that record in the o/p... (2 Replies)
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5. Shell Programming and Scripting
Hi Everyone,
a.txt
line1;a;33
line1;c;22
line1;b;0
line1;a;55
a.pl
#!/usr/bin/perl
use strict;
use warnings;
my @sorted=();
my @tmp;
my $FA;
my @F; (0 Replies)
Discussion started by: jimmy_y
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6. Shell Programming and Scripting
Hello,
I am searching for a way to calculate for example 10/100 within a shellscript and the result should be 0.1 and not just 0.
Every alternative i tried just results 0
Thank you in advance
2retti (6 Replies)
Discussion started by: 2retti
6 Replies
7. UNIX for Advanced & Expert Users
I received error "awk: division by zero" while executing the following statement.
SunOS 5.10 Generic_142900-15 sun4us sparc FJSV,GPUZC-M
echo 8 | awk 'END {printf ("%d\n",NR/$1 + 0.5);}' file1.lst
awk: division by zero
Can someone provide solution?
Thanks
Please use code... (11 Replies)
Discussion started by: kumar77
11 Replies
8. Shell Programming and Scripting
input
one two three four
0 0 0 10424
0 102 0 15091
1 298 34 11111
0 10 0 1287
scripts
awk 'NR>1{print ($1/$2) / ($3/$4)}'
awk 'NR>1{ if ($1 ||$3 ||$2|| $4 == 0) print 0; else print (($1/$2)/($3/$4))}'
error
awk: division by zero
input record number 1, file rm
source line... (9 Replies)
Discussion started by: quincyjones
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9. UNIX for Dummies Questions & Answers
hi,
The below commands result only the whole number(not giving the decimal values).
pandeeswaran@ubuntu:~$ echo 1,2,3,4|sed 's/,/\//g'|bc
0
pandeeswaran@ubuntu:~$ echo 1000,2,3|sed 's/,/\//g'|bc
166
How to make it to return the decimal values?
Thanks (5 Replies)
Discussion started by: pandeesh
5 Replies
10. UNIX for Dummies Questions & Answers
I have a function that outputs 3 lines for each result and I want to know how many results there are.
so for example
function | wc -l
24
but I want to see the result 8.
so is there a easy way to divide the result? (5 Replies)
Discussion started by: yatici
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LEARN ABOUT OSX
universal::require
UNIVERSAL::require(3) User Contributed Perl Documentation UNIVERSAL::require(3)
NAME
UNIVERSAL::require - require() modules from a variable
SYNOPSIS
# This only needs to be said once in your program.
require UNIVERSAL::require;
# Same as "require Some::Module"
my $module = 'Some::Module';
$module->require or die $@;
# Same as "use Some::Module"
BEGIN { $module->use or die $@ }
DESCRIPTION
If you've ever had to do this...
eval "require $module";
to get around the bareword caveats on require(), this module is for you. It creates a universal require() class method that will work with
every Perl module and its secure. So instead of doing some arcane eval() work, you can do this:
$module->require;
It doesn't save you much typing, but it'll make alot more sense to someone who's not a ninth level Perl acolyte.
Methods
require
my $return_val = $module->require or die $@;
my $return_val = $module->require($version) or die $@;
This works exactly like Perl's require, except without the bareword restriction, and it doesn't die. Since require() is placed in the
UNIVERSAL namespace, it will work on any module. You just have to use UNIVERSAL::require somewhere in your code.
Should the module require fail, or not be a high enough $version, it will simply return false and not die. The error will be in $@ as well
as $UNIVERSAL::require::ERROR.
$module->require or die $@;
use
my $require_return = $module->use or die $@;
my $require_return = $module->use(@imports) or die $@;
Like "UNIVERSAL::require", this allows you to "use" a $module without having to eval to work around the bareword requirement. It returns
the same as require.
Should either the require or the import fail it will return false. The error will be in $@.
If possible, call this inside a BEGIN block to emulate a normal "use" as closely as possible.
BEGIN { $module->use }
SECURITY NOTES
UNIVERSAL::require makes use of "eval STRING". In previous versions of UNIVERSAL::require it was discovered that one could craft a class
name which would result in code being executed. This hole has been closed. The only variables now exposed to "eval STRING" are the
caller's package, filename and line which are not tainted.
UNIVERSAL::require is taint clean.
COPYRIGHT
Copyright 2001, 2005 by Michael G Schwern <schwern@pobox.com>.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
See http://www.perl.com/perl/misc/Artistic.html
AUTHOR
Michael G Schwern <schwern@pobox.com>
SEE ALSO
Module::Load, "require" in perlfunc, <http://dev.perl.org/rfc/253.pod>
perl v5.16.2 2009-03-30 UNIVERSAL::require(3)