For each line of the file, the script read the two fields in the variables DAYS and PATH and execute the find command.
PATH is not a good choice for a variable because it is used by the shell.
If the header 'DAY PATH' is present in your file, it must be skipped:
Another way
Jean-Pierre.
I posted a week ago regarding this scripting question, but I need to revisit and have a few more questions answered..
User cfajohnson was extremely helpful with the archive script, but clarification on my part is needed to help steer the answer in a direction that works in this particular... (5 Replies)
I am writing a shell script for Archive Purge for the table having rows < 1 year. The shell script has to extract the rows from the table and write those extracted rows to a text file. Then from the text file, each rows will be read and deleted by means of delete query one by one. The fields will... (5 Replies)
Hi,
I am writing a shell script for archive data from a table.
The design is as follows.
Step 1:
Execute the select query and extract the data into a text file.
Step 2:
The primary key for this table is TRACKING_NUM, TRACKING_NUM_SUFFIX, TIMESTAMP_UPDATED. So These three fields will be read... (1 Reply)
Hi All,
I would like to extract specific file from a zip archive.
I have a zip archive "sample.zip".
sample.zip contains few text files and images... text1.txt, text2.txt, pic.jpg etc...
I need to read specific file "text2.txt" from "sample.zip" WITHOUT EXTRACTING the zip file.
... (4 Replies)
Hi Friends,
I have an urgent requirement.
I have many files huge in size which has occupied almost the entire disk space. The files are not being moved to the archived folder.
But at present I need to purge those files, new to shell scripting, not sure how to proceed.
Eg.
Directory... (3 Replies)
Dear all,
I have this archive: cat file.txt
archive test 02 sequence 03 02length 52
archive test 02 sequence 04 02length 52
archive test 02 sequence 05 02length 52
teste arquivo 06 sequencia 08 06 length 54
teste arquivo 06 sequencia 09 ... (8 Replies)
i all.
This one sounds so simple, but I can't get it to work. I need to delete lines with certain keywords from a file.
I have a file called defaultRules, with keywords:
IPSEC_AH
IKE_UDP
IPMP_TEST_IFACE2
Then, I have another file called rules.txt with some rules:
... (10 Replies)
Hi Unix Experts,
I am new in this filed.
I have assignment to Archive and purge the log file using shell scripts I tried I could not get the result please help me this.
Ex: test.log
requirement : using shell script I need to archive the log file and nil and the content of (test.log)... (1 Reply)
Discussion started by: johney1981
1 Replies
LEARN ABOUT DEBIAN
lastlog
LASTLOG(8) System Management Commands LASTLOG(8)NAME
lastlog - reports the most recent login of all users or of a given user
SYNOPSIS
lastlog [options]
DESCRIPTION
lastlog formats and prints the contents of the last login log /var/log/lastlog file. The login-name, port, and last login time will be
printed. The default (no flags) causes lastlog entries to be printed, sorted by their order in /etc/passwd.
OPTIONS
The options which apply to the lastlog command are:
-b, --before DAYS
Print only lastlog records older than DAYS.
-h, --help
Display help message and exit.
-R, --root CHROOT_DIR
Apply changes in the CHROOT_DIR directory and use the configuration files from the CHROOT_DIR directory.
-t, --time DAYS
Print the lastlog records more recent than DAYS.
-u, --user LOGIN|RANGE
Print the lastlog record of the specified user(s).
The users can be specified by a login name, a numerical user ID, or a RANGE of users. This RANGE of users can be specified with a min
and max values (UID_MIN-UID_MAX), a max value (-UID_MAX), or a min value (UID_MIN-).
If the user has never logged in the message ** Never logged in** will be displayed instead of the port and time.
Only the entries for the current users of the system will be displayed. Other entries may exist for users that were deleted previously.
NOTE
The lastlog file is a database which contains info on the last login of each user. You should not rotate it. It is a sparse file, so its
size on the disk is usually much smaller than the one shown by "ls -l" (which can indicate a really big file if you have in passwd users
with a high UID). You can display its real size with "ls -s".
FILES
/var/log/lastlog
Database times of previous user logins.
CAVEATS
Large gaps in UID numbers will cause the lastlog program to run longer with no output to the screen (i.e. if in lastlog database there is
no entries for users with UID between 170 and 800 lastlog will appear to hang as it processes entries with UIDs 171-799).
shadow-utils 4.1.5.1 05/25/2012 LASTLOG(8)