08-08-2006
Process launched by user who logs out, continue running ?
Lets say a user starts a process (either a shell script or a Perl script) and before that process finishes, he logs out (either intentionaly or network problems or ...), does the process continu running ?
Default shell is Korn.
This is because at my job (being trained), there are tasks to run which involves doing a bunch of commands and/or scripts to run. I was thinking about scripting the whole thing to save time and decrease human errors. But someone asked me what happens when a user logs out. That got me thinking ...
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
How do you determine what user a process is running as? I want to know what user proftpd is running as, and what user a script that I have is running as. Thanks. (1 Reply)
Discussion started by: america2
1 Replies
2. UNIX for Advanced & Expert Users
Hi all,
There is an application which can be launched once on our box and there are several suspected users telnet into the system with the same login ID.
Is there a way that i can find out from which tty the application is launched? If so, i can get the user name from the "finger"... (1 Reply)
Discussion started by: sleepy_11
1 Replies
3. UNIX for Advanced & Expert Users
On my application there are lots of users are doing there work or tasks? ...In my SSH or in 'Putty' i am observing logs?
Hot to observe one particular 'user' logs.. even through there are lots of users working on it?
For EX: i am log in with use rid:nikhil@in.com. another one log in with... (4 Replies)
Discussion started by: ksr.test
4 Replies
4. UNIX for Dummies Questions & Answers
Hello there,
I "discovered" an interesting command lastlog, but I couldn't find, until now:cool:, if it's possible to get a list of the launched process by users and root during a certain of time...
...any idea would be really appreciated!!!
Thanks in advance.
Giordano Bruno (3 Replies)
Discussion started by: Giordano Bruno
3 Replies
5. Shell Programming and Scripting
Hi.
I was testing some staff and wrote simple script, which only writes date to log every 15 seconds.
Like that
#1.sh
while true;do
echo `date` >> 1.log
sleep 15
done
And than i ran this process with `at -s -f 1.sh now`. And now it is running and i don't know how to catch it.
I tryed... (1 Reply)
Discussion started by: kukuruku
1 Replies
6. Shell Programming and Scripting
Hi there,
I'm not really stranger to Linux and shell scripting but I am to servers. Anyway, I usually run scripts on a shared science machine, accessible via ssh.
My scripts are usually run with mpi, e.g.
mpirun -np 16 ./my_script
the things after entering the science machine and running... (6 Replies)
Discussion started by: matteo86
6 Replies
7. UNIX for Dummies Questions & Answers
Hi,
When process listing, I came across a process running as user daemon.
daemon 23576 23574 0 07:32:04 ? 0:07 oracle (DESCRIPTION=(LOCAL=YES)(ADDRESS=(PROTOCOL=beq)))
root 27526 27444 1 07:38:43 ttyp5 0:00 grep 23574
why a process runs as user daemon, when it should be... (3 Replies)
Discussion started by: wilsonee
3 Replies
8. Shell Programming and Scripting
Need help in scripting . Below is the situation and need your inputs
Checking all the processes, scripts running time based on user input time . Below Example
ps -aef -o user,pid,etime,stime,args| grep sleep
<user> 28995 01:24 14:14:39 sleep 120
<user> 29385 00:52 14:15:10... (8 Replies)
Discussion started by: ajayram_arya
8 Replies
9. Shell Programming and Scripting
Good morning!
I'm trying to add Maven to the system boot by the moment without success.
Testing the operation of the script I realize that the process isn't persistent when the program is launched with the start option.
---- #Startup Script ----
#! /bin/sh
# chkconfig: 345 99 1
#... (5 Replies)
Discussion started by: carpannav
5 Replies
10. Shell Programming and Scripting
Hi,
i need to list the processes running only under current logged in user.
EX:
$ whoami
oraaqw
$ ps -ef | grep tnslsnr
oraaqw 11403300 19267592 0 09:14:47 pts/3 0:00 grep tnslsnr
oraaqw 15794208 1 0 Jan 14 - 11:59... (6 Replies)
Discussion started by: aravindadla
6 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)