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Top Forums Shell Programming and Scripting extract a portion of log file Post 302082669 by chandra004 on Thursday 3rd of August 2006 12:11:38 AM
Old 08-03-2006
We really appreciate help on this...
Basically I have file which has:
...
...
echo config_start
text1
text2
...
few lines of text
echo end_install
...

Another file has
....
...
echo config_start
echo end_install
....
I need to copy from file1 to file2.
With the sed command below, I was able to get the text from file1. But couldn't put it in file2.

Please need help on this..guys...appreciate your ideas..
I browsed in this forum and I got this lead...can/how do I use it ??

$ cat fileToEdit | sed -e "$lineToEnterNewText"' s/^\(.*\)$/\1\
'"$newText"'/' > fileToEdit

Thanks
Chandra
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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