07-23-2006
Quote:
Originally Posted by mahekr2000
I did happen to look into FAQ section before I posted it here..
datecalc is mentioned in the third sentence and it is the first solution proposed in the faq article.
9 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I Have a long file like this
123122312 05/06/12
123123456 05/06/14
I want to take the difference of dates in two lines & print difference sidewise for the whole long files.
Pl help me out. (1 Reply)
Discussion started by: vanand
1 Replies
2. Shell Programming and Scripting
Hi,
I need the date n months before currrent date
I need to store date in a varible say x
and then get the date 6 month before and get the result in the format 25-Aug-2009
Please Advice (7 Replies)
Discussion started by: mad_man12
7 Replies
3. HP-UX
Hi there,
is it possible to get the actual date minux six months with just a simple command?
It's easy with Linux but on HP Unix (for me) impossible ;)
Best wishes (3 Replies)
Discussion started by: System
3 Replies
4. Shell Programming and Scripting
I have a file with name and date---
$ cat file.log
userA 01-06-2014
userB 25-05-2014
userC 16-05-2014
userC 01-03-2014
I want to search for the current date and get the name for that date. If current date is not found, go back 1 day and search and so on till it finds the... (2 Replies)
Discussion started by: Nagesh_1985
2 Replies
5. UNIX for Dummies Questions & Answers
Hi,
I am reading a particular date from a file using below command
WFLWDATE=$(sed '2q;d' FileA.prm)
The echo command outputs the correct date in variable WFLWDATE
Now I want to subtract 5 minutes from this variable. I am on AIX and unable to get anything working as expected.
Can you... (1 Reply)
Discussion started by: vrupatel
1 Replies
6. Shell Programming and Scripting
Hi,
Can you please let me know code for the below (in korn shell)
a) Subtract month(s) from given date
b) Subtract day(s) from give date
c) Subtract month(s) from given timestamp
d) Subtract day(s) from give timestamp (1 Reply)
Discussion started by: tostay2003
1 Replies
7. Shell Programming and Scripting
Hi All,
I am getting a date from environment variable and want to do some processing by subtracting 2 months from the date passed through the environment variable.
I am trying the following syntax :
date_var=2014-08-31
date_2M_ago='$date_var+"%d%m%y" --$date_var="2 months ago" '... (3 Replies)
Discussion started by: Rahul Raj
3 Replies
8. Shell Programming and Scripting
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
Discussion started by: roshanbi
2 Replies
9. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT DEBIAN
xcalpr
XCALPR(1) General Commands Manual XCALPR(1)
NAME
xcalpr - print xcal calendar entries
SYNTAX
xcalpr [ -c ][ -x ][ -f file ][ -d dir ][ -u user ][ date-spec ]
DESCRIPTION
Xcalpr prints the contents of the xcal files. It is intended to be used in situations when you have no access to an X screen. It can also
be used to generate entries for the standard UNIX calendar program.
With no arguments, it prints any entries that exist for the next seven days. The program also reads the contents of the seven daily files
and prints them at the appropriate point in the output stream. Each line in the output is preceded by the day of the week, the day of the
month, the month and the year.
Xcalpr can be given a date specification to select months and years. If the date spec consists of just a year number, then all the data
for that year is printed. For example:
xcalpr 1994
will print all the data for 1994. Several years can be specified.
If you give the name of a month, then the data for that month in the current year will be printed. If the month is in the past, then the
data for that month next year will be printed. For example, if
xcalpr oct jan
is typed in August, xcalpr will print October in the current year and January next year.
You can select a particular year by adding the number after any months that you need printing:
xcalpr oct nov 1994
will print October and November in 1994.
There are a couple of special `month' names. The name rest will print the data for the rest of the month, starting tomorrow. The rest
argument is not recognised if you give a year as a parameter. If tomorrow happens to be the first day of the next month, then all the data
for next month will be printed. The name next prints all the data for next month.
OPTIONS
The -c option causes xcalpr to output lines suitable for input to the standard UNIX calendar program.
The -d switch is followed by a directory name and specifies an alterative location for your Calendar directory. Your home directory is
prepended if the name doesn't start with a slash or a dot.
The -f option is followed by a file name and xcalpr will write it's output to that file, rather than standard output.
The -u option is followed by a user name and dumps their calendar files rather than yours.
The -x option makes xcalev operate with Calendar files that are compatible with the xcalendar program.
FILES
$HOME/Calendar/*
xc<dd><Mon><Year> A data file is day, Month in three letter format and the year.
xy<Year> A year directory.
xw<Day> A data file for the weekly code, one per day.
SEE ALSO
xcal(1), xcalev(1), xcal_cal(1)
AUTHOR
Copyright 1993 by Peter Collinson, Hillside Systems All rights reserved.
This product includes software developed by the University of California, Berkeley and its contributors.
X Version 11 R5 October 1993 XCALPR(1)