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Top Forums UNIX for Dummies Questions & Answers bash pattern matching echo *[! '/' ] doesn't work Post 302080089 by james hanley on Saturday 15th of July 2006 08:43:58 PM
Old 07-15-2006
bash pattern matching echo *[! '/' ] doesn't work

without using ls, just using echo so purely pattern matching

I can say echo */ <-- lists directories

but how would I match files? surely something like *!/ or *[!/] but neither work ?

it seems like there isn't much that I can put in [ ] but surely i should be able to put any ascii character. but how?


thanks
 

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DATEFMT_SET_LENIENT(3)							 1						    DATEFMT_SET_LENIENT(3)

IntlDateFormatter::setLenient - Set the leniency of the parser

	Object oriented style

SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient) DESCRIPTION
Procedural style bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient) Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized tokens, or invalid values ("February 30th") are not accepted. PARAMETERS
o $fmt - The formatter resource o $lenient - Sets whether the parser is lenient or not, default is TRUE (lenient). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 datefmt_set_lenient(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'dd/MM/yyyy' ); echo 'lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } datefmt_set_lenient($fmt, false); echo " Now lenient of the formatter is : "; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : ".intl_get_error_message(); echo " Error_code is : ".intl_get_error_code(); } ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'dd/MM/yyyy' ); echo 'lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } $fmt->setLenient(FALSE); echo " Now lenient of the formatter is : "; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> The above example will output: lenient of the formatter is : TRUE Trying to do parse('35/13/1971'). Result is : 66038400 Now lenient of the formatter is : FALSE Trying to do parse('35/13/1971'). Result is : Error_msg is : Date parsing failed: U_PARSE_ERROR Error_code is : 9 SEE ALSO
datefmt_is_lenient(3), datefmt_create(3). PHP Documentation Group DATEFMT_SET_LENIENT(3)
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