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Top Forums UNIX for Dummies Questions & Answers bash pattern matching echo *[! '/' ] doesn't work Post 302080089 by james hanley on Saturday 15th of July 2006 08:43:58 PM
Old 07-15-2006
bash pattern matching echo *[! '/' ] doesn't work

without using ls, just using echo so purely pattern matching

I can say echo */ <-- lists directories

but how would I match files? surely something like *!/ or *[!/] but neither work ?

it seems like there isn't much that I can put in [ ] but surely i should be able to put any ascii character. but how?


thanks
 

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DATEFMT_IS_LENIENT(3)							 1						     DATEFMT_IS_LENIENT(3)

IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public bool IntlDateFormatter::isLenient (void ) DESCRIPTION
Procedural style bool datefmt_is_lenient (IntlDateFormatter $fmt) Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient. EXAMPLES
Example #1 datefmt_is_lenient(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'dd/mm/yyyy' ); echo 'lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } datefmt_set_lenient($fmt,false); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, "dd/mm/yyyy" ); echo "lenient of the formatter is : "; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0){ echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } $fmt->setLenient(FALSE); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> The above example will output: lenient of the formatter is : TRUE Trying to do parse('35/13/1971'). Result is : -2147483 Now lenient of the formatter is : FALSE Trying to do parse('35/13/1971'). Result is : Error_msg is : Date parsing failed: U_PARSE_ERROR Error_code is : 9 SEE ALSO
datefmt_set_lenient(3), datefmt_create(3). PHP Documentation Group DATEFMT_IS_LENIENT(3)
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