Hi
In my shell script, I'm trying to find the line count of a file and assign it to a variable.
LINE_COUNT=$(wc -l $FILE_NAME)
But when i display LINE_COUNT, i'm getting the linecount concatenated with the file name. I want only the number. How can i get the line count alone ? Someone... (2 Replies)
hi all,
in ksh, how do i assign the output of a find command to a variable, e.g
am trying something like this :
totalNoFiles=$(print find ./ -name "SystemOut*.log");
but when i echo $totalNoFiles it displays
find ./ -name "SystemOut*.log"
instead of the total number of... (2 Replies)
can we make a global variable and store character values and add other values to that variable ?? for example
a="hello, John"
and can we add value ". How are you? so
a can have
"hello, John. How are you?"
can someone help me?? (2 Replies)
Hi folks.
I have this variable called FirstIN that contains something like this: 001,002,003,004...
I am trying to assign the content of this variable into ModifiedIN but with the following format : 001 002 003 004...(changing the commas for spaces)
I thought about using sed but i am not... (17 Replies)
my script is some thing like this
i11="{1,2,3,4,5,6,7,8,9,10,11,}"
echo "enter value"
read value ..............suppose i11
x="$value"
echo "$($value)" .............the echo should be {1,2,3,4,5,6,7,8,9,10,11,}
but its showing "i11" only.
plz help me out to get desired... (10 Replies)
Hi,
I have a list of files in a directory. Each file has a .txt and a .log extension i.e. file.txt & file.log, file1.txt & file1.log etc. The file with the .log extension may not always exist alongside the file with the .txt extension.
I need to copy the .txt file if there is a corresponding... (6 Replies)
Hi
I have a script that accepts an input date in YYYY-MM-DD format.
After that, I used sed to delete the hyphen (-) which gives me an output YYYY MM DD.
My question is, how can I assign those three numbers to a three different variable.
Example:
2013-11-23 will become 2013 11 23... (4 Replies)
Unable to get the value to a variable.
set -x
cd $HOME
echo "Enter the server name"
read a
echo $a
i=4
j=1
k = ps -ef | awk '/server1/{ print $4 }' | tail -$i | head -$j`
echo $k
When I do the same in command line it works, however the same does not work when I provide that in the... (1 Reply)
I have a date column as 06302015 but I need to have variable which extracts 063015.
Am trying something like below but it is not assigning
Please let me know if am missing something. Thanks in advance.
################################
#!/usr/bin/ksh
DT=06302015
... (7 Replies)
Discussion started by: weknowd
7 Replies
LEARN ABOUT LINUX
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)