07-14-2006
Epoch time is actually time passed in seconds since Epoch - 00:00:00 UTC January 1, 1970. What you will end up with after subtraction is difference between the two times in seconds. You just have to convert this to minutes:hours if you need.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Guys, i have a question...
I have 2 sets of data say "a" and "a+1" which has values in epoch time..
Question is... if i were to get the time difference where diff = "a+1" - "a"
can i convert it back to real time duration after the subtraction...
OR i need to convert em first before i do the... (1 Reply)
Discussion started by: 12yearold
1 Replies
2. Shell Programming and Scripting
Hi,
i need to convert below date/time format into epoch time
YYYY-m-d H:M
below the example:
a=`date +"%F %H:%M"`
echo $a
Convert $a to epoch time
------------------------------------------------------------------------
lets take an example
if $a=1.03
here i want the epoch time... (3 Replies)
Discussion started by: ali560045
3 Replies
3. Shell Programming and Scripting
I have a file named "suspected" with series of line like these :
{'protocol': 17, 'service': 'BitTorrent KRPC', 'server': '219.78.120.166', 'client_port': 52044, 'client': '10.64.68.44', 'server_port': 8291, 'time': 1226506312L, 'serverhostname': ''}
{'protocol': 17, 'service': 'BitTorrent... (3 Replies)
Discussion started by: rk4k
3 Replies
4. Shell Programming and Scripting
Hi guys,
I know that this topic has been discuss numerous times, and I have search the net and this forum for it.
However, non able to address the problem I faced so far.
I am on Solaris Platform and unable to install additional packages like the GNU date and gawk to make use of their... (5 Replies)
Discussion started by: DrivesMeCrazy
5 Replies
5. Shell Programming and Scripting
Hi,
Is there any easy way to convert date time(stored in shell variable ) to epoch time in solaris box? As +%s is working on linux but not on solaris, also -d option is not working.
Any suggestion please? (6 Replies)
Discussion started by: anshuman0507
6 Replies
6. Shell Programming and Scripting
Hi all,
I got a file with epoch times like this.
1264010700
1264097400
1263529800
1263762900
1263924300
What I want.
I want all epoch times which are > current epoch time written to a file. So everything that is < will be ignored and not written to the file.
Thanks (3 Replies)
Discussion started by: stinkefisch
3 Replies
7. Shell Programming and Scripting
Dear experts,
I have an epoch time input file such as : -
1302451209564
1302483698948
1302485231072
1302490805383
1302519244700
1302492787481
1302505299145
1302506557022
1302532112140
1302501033105
1302511536485
1302512669550
I need the epoch time above to be converted into real... (4 Replies)
Discussion started by: aismann
4 Replies
8. Solaris
One way of getting epoch time in solaris is
truss date 2>&1 | awk '/^time/{print $3}'
Is there any other simple command that can be run from Korn Shell to display epoch time in solaris 5.10? (3 Replies)
Discussion started by: indianya
3 Replies
9. Shell Programming and Scripting
# date +%s -d "Mon Feb 11 02:26:04"
1360567564
# perl -e 'print scalar localtime(1360567564), "\n";'
Mon Feb 11 02:26:04 2013
the epoch conversion is working fine. but one of my application needs 13 digit epoch time as input
1359453135154
rather than 10 digit epoch time 1360567564... (3 Replies)
Discussion started by: vivek d r
3 Replies
10. Shell Programming and Scripting
I have a list of epoch times delimited by "-" as follows:
1335078000 - 1335176700
1335340800 - 1335527400
1335771300 - 1335945600
1336201200 - 1336218000
The corresponding dates are:
20120422 1000 - 20120423 1325
20120425 1100 - 20120427 1450
20120430 1035 - 20120502 1100 ... (3 Replies)
Discussion started by: alex2005
3 Replies
LEARN ABOUT DEBIAN
datetime::format::epoch::dotnet
DateTime::Format::Epoch::DotNet(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::DotNet(3pm)
NAME
DateTime::Format::Epoch::DotNet - Convert DateTimes to/from .NET epoch seconds
SYNOPSIS
use DateTime::Format::Epoch::DotNet;
my $dt = DateTime::Format::Epoch::DotNet->parse_datetime( 1051488000 );
DateTime::Format::Epoch::DotNet->format_datetime($dt);
# 1051488000
my $formatter = DateTime::Format::Epoch::DotNet->new();
my $dt2 = $formatter->parse_datetime( 1051488000 );
$formatter->format_datetime($dt2);
DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
epoch defined in the .NET Framework SDK.
Note that this epoch is defined in the local time zone. This means that these two pieces of code will print the same number of seconds,
even though they represent two datetimes 6 hours apart:
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'Europe/Amsterdam' );
print $formatter->format_datetime($dt);
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'America/Chicago' );
print $formatter->format_datetime($dt);
METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor.
o new()
Constructor of the formatter/parser object. It has no parameters.
SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.
AUTHOR
Eugene van der Pijll <pijll@gmx.net>
COPYRIGHT
Copyright (c) 2003 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it
under the same terms as Perl itself.
SEE ALSO
DateTime
datetime@perl.org mailing list
perl v5.10.1 2007-12-03 DateTime::Format::Epoch::DotNet(3pm)