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Top Forums UNIX for Advanced & Expert Users reg no of instances of a script run using cron Post 302079812 by kamesh83 on Thursday 13th of July 2006 05:49:11 AM
Old 07-13-2006
Lightbulb reg no of instances of a script run using cron

I have the below code in a file called test.ksh and it is scheduled using cron forevery 5 min. when i see the cron out file for every 5 min it showing the no of process running are 2. same thing when i implement in another script which contains other code along with the below code , it showing as 1. why?
Both the scripts were scheduled using cron.

echo "Cron process testing "
echo `ps -ef |egrep 'test.ksh'|egrep -v grep`
a=`ps -ef |egrep 'test.ksh'|egrep -vc grep`
echo "No of process running :$a" Smilie
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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