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Full Discussion: date formatting
Top Forums Shell Programming and Scripting date formatting Post 302079241 by jim mcnamara on Friday 7th of July 2006 03:56:05 PM
Old 07-07-2006
try:
Code:
#!/bin/ksh

reformat()
{
    echo "$1" | tr -s '/' ' ' | read month day year
    echo "$year""$month""$day"
}

for dt in 01/10/1999 10/01/2000 12/30/2006 
do
	echo "$(reformat "$dt" )"
done

 

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CAL_TO_JD(3)								 1							      CAL_TO_JD(3)

cal_to_jd - Converts from a supported calendar to Julian Day Count

SYNOPSIS
int cal_to_jd (int $calendar, int $month, int $day, int $year) DESCRIPTION
cal_to_jd(3) calculates the Julian day count for a date in the specified $calendar. Supported $calendars are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $calendar - Calendar to convert from, one of CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH or CAL_FRENCH. o $month - The month as a number, the valid range depends on the $calendar o $day - The day as a number, the valid range depends on the $calendar o $year - The year as a number, the valid range depends on the $calendar RETURN VALUES
A Julian Day number. SEE ALSO
cal_from_jd(3), frenchtojd(3), gregoriantojd(3), jewishtojd(3), juliantojd(3), unixtojd(3). PHP Documentation Group CAL_TO_JD(3)
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