07-04-2006
can I pass awk variable to system command?
I wanna use a system function to deal with several data. So I use awk variable FILENAME to transfer the file directory to system command, but it does not work.
I use a shell function "out_function" to deal with data and save the result in another directory with the same file name.
How can I do it?
My code is as follows:
#try.awk
{system("./out_function FILENAME > ./dst/FILENAME")
print FILENAME
nextfile
}
I use command ---awk -f try.awk ./src/* --- to open data files. I found that system("
command") could not recongnize FILENAME, so it could not run correctly. How
ever, my test command--print FILENAME-- runs correctly.
How should I do to solve this problem? Thanks a lot.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
i would like to pass a variable to awk wherein the variable comes from external loop.
i tried this...
let x=0
until test $x -eq 32
do
cat file | awk '{ print $1 , "Number" , $($x) }' >> output
done
thanks, (4 Replies)
Discussion started by: inquirer
4 Replies
2. Shell Programming and Scripting
I am trying to pass 2 shell variable's ("START" and "END") define earlier in the script to this awk statement, but i can't seem to pass it on. PLs help.
set START = xxxx
set END = yyyy
set selected_file = `awk '/$START/,/$END/' filename` (24 Replies)
Discussion started by: Raynon
24 Replies
3. UNIX for Dummies Questions & Answers
I have an awk statement where I Need to pass an environment variable but I cannot get it to work:
My evironment varible examples below:
$FILE1=/dev/fs/file.new
$FILE2=/dev/fs/file.old
Code below:
awk -F"|" '
BEGIN {
while( getline < "$FILE1" )
{ arr=1 }
}
arr != 1 { print }
'... (12 Replies)
Discussion started by: eja
12 Replies
4. Shell Programming and Scripting
Hi
I want to pass variables with the NR function in awk command.
test_file1 is input file having 500 records.
var1=100.
var2=200
awk -F" " 'NR >= $var1 && NR <= $var2' test_file1 > test_file2.
My end result should be that test_file2 should have records from line number between... (2 Replies)
Discussion started by: Nishithinfy
2 Replies
5. Shell Programming and Scripting
Does anyone know of a way to do something similar to this with awk and kill? I want to create the variable in awk and pass that variable to kill.
ps -ef | grep -i chromium | awk '{$2=x}' | kill -9 $x 2>/dev/null (9 Replies)
Discussion started by: cokedude
9 Replies
6. Shell Programming and Scripting
Hello,
I'm having some issues getting a home dir from a remote server passed to a variable.
Here is what I have so far:
rsh server "(ls -ld /home*/user | awk '{print \$9}')"
/home3/userThat works fine and brings back what I need.
But when I try to add it to a variable it goes all... (3 Replies)
Discussion started by: elcounto
3 Replies
7. Shell Programming and Scripting
Hi
I need your help, please
How can I pass arguments to system command in a awk script?... for example:
byte=substr(cadena,pos,2);
system("grep -n byte mapeo.txt");
Does it exist a way?
Thanks for advance. (4 Replies)
Discussion started by: solaris21
4 Replies
8. Shell Programming and Scripting
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk... (2 Replies)
Discussion started by: Ashunayak
2 Replies
9. UNIX for Advanced & Expert Users
I must have forgot how to do this, but, I am attempting to enter a variable into an awk / gawk search pattern.
I am getting a value from user input to place in a specific section of a 132 character string.
my default command is ....
gawk --re-interval '/^(.{3}P .{4}CYA.{8}1)/' ... (3 Replies)
Discussion started by: sdeevers
3 Replies
10. UNIX for Beginners Questions & Answers
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies
LEARN ABOUT DEBIAN
gnunet-rsa
GNUNET-RSA(1) General Commands Manual GNUNET-RSA(1)
NAME
gnunet-rsa - manipulate GNUnet RSA key files
SYNOPSIS
gnunet-rsa [options]FILENAME
DESCRIPTION
gnunet-rsa can be used to create an RSA private key and to print the corresponding public key. You must specify a filename containing an
RSA private key in GNUnet format as an argument. If the file does not exist, gnunet-rsa will create a key. This may then take a while.
If the option -p is given, the corresponding public key will be printed to the console.
OPTIONS
-p, --print-public-key
Print the corresponding public key to stdout.
-P, --print-peer-identity
Print the corresponding peer identity (hash of the public key) to stdout. This hash is used for the name of peers.
-s, --print-short-identity
Print the corresponding short hash (256-bit hash of the public key) to stdout. This hash is used for names in the zkey zone.
-c FILENAME, --config=FILENAME
Use the configuration file FILENAME.
-h, --help
Print short help on options.
-L LOGLEVEL, --loglevel=LOGLEVEL
Use LOGLEVEL for logging. Valid values are DEBUG, INFO, WARNING and ERROR.
-v, --version
Print GNUnet version number.
BUGS
Report bugs by using Mantis <https://gnunet.org/bugs/> or by sending electronic mail to <gnunet-developers@gnu.org>
GNUnet Mar 15, 2012 GNUNET-RSA(1)