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Top Forums Shell Programming and Scripting help to retrive data from log file Post 302078657 by jim mcnamara on Monday 3rd of July 2006 04:10:25 PM
Old 07-03-2006
I think the OP wants all data from Jun 30 :

Code:
#!/bin/ksh
awk '{ if (index($0,"***")>0){
         printf("\n%s|",$0)} 
         else{printf("%s|", $0)} 
      }' filename | \
      grep 'Jun 30'  | tr -s '|' '\n' | grep 'Generation'

Without resorting to add-on perl modules(DATE::str2time), I cannot think of a way to find the max date other than
Code:
tail -5 filename

 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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