AWK question? Post: 302077603

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I have the following error: ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }' Syntax Error The source line is 1. The error context is BEGIN >>> NR <<< > 1 { print $2, $9 } awk: 0602-500 Quitting The source line is 1. What I want to do is ls a directory, skip the first...

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Hello, I have the following command that does 2 searches. awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE How do I search up after the first search? thanks

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i have a little awk script that I use looks this: awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled. i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled....

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I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text. Can anyone provide some assistance. Thanks!!

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How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06 4.35109e+06 4.36134e+06 4.4535e+06 5.47752e+06 5.48777e+06 7.52554e+06 7.73036e+06 9.06158e+06 :confused: thank you

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Can anyone help with this this one liner: nawk -v RS='' '$1=$1' InputFile What I have in the file: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958 -0.0005763523138347 0.0 And the output I want: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958...

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Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello...

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awk question.

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: im using ls -l | xargs | awk '{what ever files here}' im trying to get something that looks like this...

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awk question : system output to awk variable.

Hi Experts, I am trying to get system output to capture inside awk , but not working: Please advise if this is possible : I am trying something like this but not working, the output is coming wrong: echo "" | awk '{d=system ("date") ; print "Current date is:" , d }' Thanks,

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spi_modifytuple

SPI_MODIFYTUPLE(3)					  PostgreSQL 9.2.7 Documentation					SPI_MODIFYTUPLE(3)

NAME

       SPI_modifytuple - create a row by replacing selected fields of a given row

SYNOPSIS

       HeapTuple SPI_modifytuple(Relation rel, HeapTuple row, int ncols,
				 int * colnum, Datum * values, const char * nulls)

DESCRIPTION

       SPI_modifytuple creates a new row by substituting new values for selected columns, copying the original row's columns at other positions.
       The input row is not modified.

ARGUMENTS

       Relation rel
	   Used only as the source of the row descriptor for the row. (Passing a relation rather than a row descriptor is a misfeature.)

       HeapTuple row
	   row to be modified

       int ncols
	   number of column numbers in the array colnum

       int * colnum
	   array of the numbers of the columns that are to be changed (column numbers start at 1)

       Datum * values
	   new values for the specified columns

       const char * Nulls
	   which new values are null, if any (see SPI_execute_plan for the format)

RETURN VALUE

       new row with modifications, allocated in the upper executor context; NULL only if row is NULL

       On error, SPI_result is set as follows:

       SPI_ERROR_ARGUMENT
	   if rel is NULL, or if row is NULL, or if ncols is less than or equal to 0, or if colnum is NULL, or if values is NULL.

       SPI_ERROR_NOATTRIBUTE
	   if colnum contains an invalid column number (less than or equal to 0 or greater than the number of column in row)

PostgreSQL 9.2.7						    2014-02-17							SPI_MODIFYTUPLE(3)

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spi_modifytuple