AWK question? Post: 302077515

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I have the following error: ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }' Syntax Error The source line is 1. The error context is BEGIN >>> NR <<< > 1 { print $2, $9 } awk: 0602-500 Quitting The source line is 1. What I want to do is ls a directory, skip the first...

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How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06 4.35109e+06 4.36134e+06 4.4535e+06 5.47752e+06 5.48777e+06 7.52554e+06 7.73036e+06 9.06158e+06 :confused: thank you

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Can anyone help with this this one liner: nawk -v RS='' '$1=$1' InputFile What I have in the file: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958 -0.0005763523138347 0.0 And the output I want: 0.0013985457223116 -0.0002338180925628 0.0 0.0003709430584958...

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Basic awk question...getting awk to act on $1 of the command itself

I have a script problem that I am not able to solve due my very limited understanding of unix/awk. This is the contents of test.sh awk '{print $1}' From the prompt if I enter: ./test.sh Hello World I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello...

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Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: im using ls -l | xargs | awk '{what ever files here}' im trying to get something that looks like this...

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LEARN ABOUT PHP

db2_field_name

DB2_FIELD_NAME(3)							 1							 DB2_FIELD_NAME(3)

db2_field_name - Returns the name of the column in the result set

SYNOPSIS

       string db2_field_name (resource	$stmt, mixed  $column)

DESCRIPTION

	Returns the name of the specified column in the result set.

PARAMETERS

	      o $stmt
		- Specifies a statement resource containing a result set.

	      o $column
		-  Specifies  the  column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
		string containing the name of the column.

RETURN VALUES

	Returns a string containing the name of the specified column. If the specified column does not exist in the result set,  db2_field_name(3)
       returns FALSE.

SEE ALSO

       db2_field_display_size(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3).

PHP Documentation Group 													 DB2_FIELD_NAME(3)

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db2_field_name