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Full Discussion: Problem with File path
Top Forums Shell Programming and Scripting Problem with File path Post 302077066 by sandeep_hi on Monday 19th of June 2006 08:53:55 AM
Old 06-19-2006
Problem with File path

How to pass a file path to open a file?
I am using cygwin.
I want to open a file from a particular path, say C:\Test\File1,. This file path is stored in a variable.
I am able to cat a file like this :
cat "c:\Test\File1"
but i want the same thing to happen in my script file through a variable and it is not working this way.

Eg:
v1="C:\Test\Ad.A"
v2="C:\Test\Ar.A"
gawk -v file2=$v1 -f prog.awk $v2

Please help in this regard
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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