06-03-2006
In your code,
echo "-----" "$LINE" "-----"
Remove the double quotes around $LINE. I think it should work.
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LEARN ABOUT PHP
imagickdraw.line
IMAGICKDRAW.LINE(3) 1 IMAGICKDRAW.LINE(3)
ImagickDraw::line - Draws a line
SYNOPSIS
bool ImagickDraw::line (float $sx, float $sy, float $ex, float $ey)
DESCRIPTION
Warning
This function is currently not documented; only its argument list is available.
Draws a line on the image using the current stroke color, stroke opacity, and stroke width.
PARAMETERS
o $sx
- starting x coordinate
o $sy
- starting y coordinate
o $ex
- ending x coordinate
o $ey
- ending y coordinate
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
ImagickDraw.line(3)
<?php
function line($strokeColor, $fillColor, $backgroundColor) {
$draw = new ImagickDraw();
$draw->setStrokeColor($strokeColor);
$draw->setFillColor($fillColor);
$draw->setStrokeWidth(2);
$draw->setFontSize(72);
$draw->line(125, 70, 100, 50);
$draw->line(350, 170, 100, 150);
$imagick = new Imagick();
$imagick->newImage(500, 500, $backgroundColor);
$imagick->setImageFormat("png");
$imagick->drawImage($draw);
header("Content-Type: image/png");
echo $imagick->getImageBlob();
}
?>
PHP Documentation Group IMAGICKDRAW.LINE(3)