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Full Discussion: stupid IP question
Special Forums IP Networking stupid IP question Post 302074159 by tf0 on Saturday 20th of May 2006 06:58:00 PM
Old 05-20-2006
Quote:
Originally Posted by sugarsweet
Hello!.
Could someone explain to me if two computers, say in a large city, could have the same IP address on different days, if they were using broadband internet?
It is possible on any type of service that is DHCP driven, whether it be a few people requesting or a thousands.

Quote:
Or, is it possible an internet service provider could assign a static IP address to ALL computers using its service for a period of a week or so? (As a sort of security measure?)
No. This would not work.

Quote:
In fact... I guess I am just confused about IP addresses in general. Does each computer get a *specific* one or can they be assigned to routers etc. without indicating a certain computer?
Thank you!!!
Think of IPs as something that is borrowed whenever anything asks for it.

Quote:
Originally Posted by stdout
hello,

a good IP allocation engineering maybe wont do that. they use the form of NAT and NAT and NAT and NAT again and so on - plus with the help of proxy, and DHCP - so even if you have been allocated with a non private IP addr (or so called a public IP) your real IP still invisible to the internet.

cheers...
[NAT*NAT++]+proxy+dhcp is what you're suggesting. IP addresses aren't "invisible to the internet."

Quote:
Originally Posted by buffoonix
Because of the limited pool and the great demand it happens regularily that the next client in the queue gets the very same IP address someone else have been holding so far once he quits or gets kicked of (which forcebly happens at least once a day even for DSL clients of many ISPs)
It is not regular for an internet service provider's DHCP server to break lease to reassign to another address requesting device due to a shallow allocation. This does not "happen daily " and it doesn't matter what kind of connection.

Last edited by tf0; 05-20-2006 at 08:04 PM..
 

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NAT action in tc(8)						       Linux						       NAT action in tc(8)

NAME
nat - stateless native address translation action SYNOPSIS
tc ... action nat DIRECTION OLD NEW DIRECTION := { ingress | egress } OLD := IPV4_ADDR_SPEC NEW := IPV4_ADDR_SPEC IPV4_ADDR_SPEC := { default | any | all | in_addr[/{prefix|netmask}] DESCRIPTION
The nat action allows to perform NAT without the overhead of conntrack, which is desirable if the number of flows or addresses to perform NAT on is large. This action is best used in combination with the u32 filter to allow for efficient lookups of a large number of stateless NAT rules in constant time. OPTIONS
ingress Translate destination addresses, i.e. perform DNAT. egress Translate source addresses, i.e. perform SNAT. OLD Specifies addresses which should be translated. NEW Specifies addresses which OLD should be translated into. NOTES
The accepted address format in OLD and NEW is quite flexible. It may either consist of one of the keywords default, any or all, represent- ing the all-zero IP address or a combination of IP address and netmask or prefix length separated by a slash (/) sign. In any case, the mask (or prefix length) value of OLD is used for NEW as well so that a one-to-one mapping of addresses is assured. Address translation is done using a combination of binary operations. First, the original (source or destination) address is matched against the value of OLD. If the original address fits, the new address is created by taking the leading bits from NEW (defined by the netmask of OLD) and taking the remaining bits from the original address. There is rudimental support for upper layer protocols, namely TCP, UDP and ICMP. While for the first two only checksum recalculation is performed, the action also takes care of embedded IP headers in ICMP packets by translating the respective address therein, too. SEE ALSO
tc(8) iproute2 12 Jan 2015 NAT action in tc(8)
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