I do ls -l ABC*, I get arg list too long message. This will not happen if ABC* has small no of files I believe 4000 files is limit. Any way of avoiding this.
I even tried like this
for i in `ls -l ABC*`
do
echo $i
done
Same problem.
Any solution would be great.
I am on HP-UX... (5 Replies)
hi everyone,
We have a heck of a lot of files in a particular directory and I need to search through all of them to find a list of all files containing particular text strings...one being a date and the other being the name of the report that is printed on the files.....
I've tried the... (6 Replies)
echo dirname/filename* | xargs ls -t
As a substitute doesn't give the results desired when I exceed the buffer size. I still want the files listed in chronological order, unfortunately xargs releases the names piecemeal...does anyone have any ideas? :( (4 Replies)
Hi,
I am trying to perform this task:
tar -cvf tar.newfile ??????.bas
I got error "arg list too long". Is ther any way around? I have about 1500 file need to be tar together.
Thanks in advance (5 Replies)
Hey guys. I have a program written in which i am trying to get the files from one remote machine and transferring the files to another remote machine using SCP.
It works fine for 50 or 60 files but when the files grows to 250 then i get an error message stating "Arg list too long".
#scp -p... (5 Replies)
Hi,
Help. I have a file that contains a list of users in a file. I want to cat the content of the file and feed it into sed to a preformated report. The error I got is "ksh: /usr/bin/sed: arg list too long" My method below.
A=`cat FILE1.txt`
B=`echo $A`
sed "s#USERLIST#$B#" FILE2 >... (2 Replies)
Hi,
I wanted a script to find sum of files for a particular date, below is my script
ls -lrt *.req | nawk '$6 == "Aug"' | nawk '$7 == "1"'| awk '{sum = sum + $5} END {print sum}'
However, i get the error below
/usr/bin/ls: arg list too long
How do i fix that.
Many thanks before. (2 Replies)
Hello,
I'm trying to search through 30,000 files in 1 directory, and am getting the "arg list too long" error. I've searched this forum and have been playing around with xargs and can't get that to work either. I'm using ksh on Solaris.
Here's my original code:
nawk "/Nov 21/{_=2}_&&_--"... (14 Replies)
Hello All,
I am trying to find a file name with .sh exention from a list of .dat files inside a directory.
find /app/folder1/* -name '*.dat'| xargs grep '.sh'
ksh: /usr/local/bin/find: arg list too long
Please help me finding the command.
Thanks (3 Replies)